更改图像onmouseover和onmouseout
I'm coding with php, I want to make a simple image change when hovering on it. I'm using this code:
echo '<li class="'.$icon['footer_social_icon'].'">
<img src="../wp-content/uploads/img1.png"
onmouseover="this.src="../wp-content/uploads/img2.png";"
onmouseout="this.src="../wp-content/uploads/img1.png";"/>
</li></ul>';
I don't know why it doesn't work!
我正在使用php进行编码,我希望在将鼠标悬停在其上时进行简单的图像更改。 我正在使用此代码: p>
echo'&lt; li class =“'。$ icon ['footer_social_icon']。'”&gt;
&lt; img src = “../wp-content/uploads/img1.png"
onmouseover =”this.src =“../ wp-content / uploads / img2.png”;“
onmouseout =”this.src =“。 ./wp-content/uploads/img1.png";"/>
&lt; / li&gt;&lt; / ul&gt;';
code> pre>
我不喜欢 不知道为什么它不起作用! p>
div>
Look at the quotes
onmouseover="this.src="../wp-content/uploads/img2.png";"
That is why it fails. You need to use escaped single quotes since you are using php to output the HTML
onmouseover="this.src=\'../wp-content/uploads/img2.png\';"
epascarello's answer will probably do the trick.
You can also place both images as separate images in the li, and change them with CSS.
echo '<li class="'.$icon['footer_social_icon'].'">
<img src="../wp-content/uploads/img1.png" class="img1" />
<img src="../wp-content/uploads/img2.png" class="img2" />
</li></ul>';
CSS:
.img2 {
display: none;
}
li:hover .img1 {
display:none;
}
li:hover .img2 {
display: inline; /* Or block, whichever you prefer */
}
This way will also work on computers without javascript.
A better approach might be to just use CSS because you don't have to worry too much about coding.
in CSS do the following:
.icon {
background-image: url('/the-name-of-your-image.png');
width: 100px; /* width of your image */
height: 100px; /* height of your image */
}
.icon:hover {
background-image: url('/the-image-when-you=hover.png');
}
Your HTML would look something like this:
<li class="icon"></li>
When someone moves their mouse over the LI element CSS will change the image to the one in the icon:hover, and then when you move the mouse off the LI element it will revert back to it's original.