PHP preg_match在<td>中提取日期/时间并转换为Unix时间

问题描述：

In my code I am trying to extract date/time only from <td> and then want to convert it into Unix time-stamp but I am stuck at extracting preg_match_all() function it won't show anything when I use $result[0] or $result[1]. I don't know why but when I dump the array I got following result:

My Array

Array
(
    [0] => Array
        (
            [0] => <td align="left" valign="top">02 April 2017 | 05:55 PM</td>
        )

    [1] => Array
        (
            [0] => 02 April 2017 | 05:55 PM
        )

)

Here is my PHP code

preg_match_all('/<td align="left" valign="top">([^"]*)<\/td>/', $printtable, $result);
var_dump($result);

在我的代码中，我只想从＆lt; td＆gt; code>中提取日期/时间然后想把它转换成Unix时间戳，但是我坚持解析 preg_match_all（） code>函数，当我使用 $ result [0] code>时它不会显示任何内容 $结果[1] 代码>。我不知道为什么，但是当我转储数组时，我得到了以下结果： p>

我的数组 p>


 数组
（
  [0] =＆gt;数组
（
 [0] =＆gt;＆lt; td align =“left”valign =“top”＆gt; 02 April 2017 | 05:55 PM＆lt; / td＆gt; 
）
  
 [1] =＆gt;数组
（
 [0] =＆gt; 2017年4月2日| 05:55 PM 
）
 
）
  code>  pre> 
 
  这是我的PHP代码 p> 
 
 
  preg_match_all（'/＆lt; td align =“left”valign =“top”＆gt;（[^“] *）＆lt;  \ / td＆gt; /'，$ printtable，$ result）; 
var_dump（$ result）; 
  code>  pre> 
  div>

答

preg_match_all returns a multidimensional array, not a single element array like preg_match. Your capture group is $result[1][0] (the 1 index is the first capture group, all other indices are additional capture groups). To convert the string to unix time you can use strtotime with str_replace (to get it to a format strtotime can handle, you also could use preg_replace and strip all non alphanumerical/space characters).

echo strtotime(str_replace('|', '', '02 April 2017 | 05:55 PM'));

Demo: https://3v4l.org/MsOlv

PHP preg_match在中提取日期/时间并转换为Unix时间

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