从数据库中删除使用php和ajax,js
问题描述:
User is login and he want to delete his status.
<p><?php echo $status; ?></p> //this shows status
<a href="" id="<?php echo $upid; ?>" class="delete">Delete</a>
here is javascript ajax code below
<script type="text/javascript" >
$(function() {
$(".delete").click(function(){
var del_id = element.attr("id");
var info = 'id=' + del_id;
if(confirm("Sure you want to delete this update? There is NO undo!"))
{
$.ajax({
type: "POST",
url: "delete.php",
data: info,
success: function(){
}
});
$(this).parents(".record").animate({ backgroundColor: "#fbc7c7" }, "fast")
.animate({ opacity: "hide" }, "slow");
}
return false;
});
});
</script>
and this is my delete.php
<?php
include("includes/db_connect.php");
if(isset($_GET['id'])){
$delete_id = $_GET['id'];
$delete_query = "delete from user_posts where upid='$delete_id'";
mysqli_query($con, $delete_query);
}
?>
User profile link is profile.php?id=1 This id is user ID.. not post ID.. when i move my mouse to delete button, at the bottom it shows profile id, not delete id. help me out.
用户登录后他想删除自己的状态。 p>
&lt; p&gt;&lt;?php echo $ status; ?&GT;&LT; / p为H. //这显示状态
&lt; a href =“”id =“&lt;?php echo $ upid;?&gt;” 类= “删除” &GT;删除&LT; / A&GT;
code> pre>
这里是javascript ajax代码 p>
&lt; script type =“text / javascript”&gt; \ n $(function(){
$(“。delete”)。click(function(){
var del_id = element.attr(“id”);
var info ='id ='+ del_id; \ nif(确认(“当然你要删除此更新?没有撤消!”))
{
$ .ajax({
type:“POST”,
url:“delete.php”,
data: info,
success:function(){
}
});
$(this).parents(“。record”)。animate({backgroundColor:“#fbc7c7”},“fast”)
。 animate({opacity:“hide”},“slow”);
}
return false;
});
});
&lt; / script&gt;
code> pre>
这是我的delete.php p>
&lt;?php
include(“includes / db_connect.php”);
if(isset($ _ GET ['id'])){
$ delete_id = $ _GET ['id'];
$ delete_query =“从user_posts删除,其中upid ='$ delete_id'”;
mysqli_query($ con,$ delete_query);
}
?&gt;
code> pre>
用户个人资料链接是profile.php?id = 1 这个id是用户ID ..不是帖子ID ..当我将鼠标移动到删除按钮时,在底部显示配置文件ID,而不是删除ID。 帮助我。 p>
答
Change to,
if(isset($_POST['id'])){
$delete_id = $_POST['id'];
答
type: "POST",
change this to "GET".
Otherwise you won't find the value in $_GET.