从存储在另一个动态变量中的日期中减去动态值
问题描述：
I need to subtract a number of days from a date which is stored in a dynamic variable '$workdate' .
The number of days to be subtracted from the date is also generating dynamically.
$workdate=date('d/m/y', strtotime($wdate)); //$wdate is a date selected from date picker and passed from previous page.
I have a variable named '$deduc' whose value is dynamically generating. suppose $deduc=2 now I need to do:
$workdate-$deduc=?
$workdate=date('d/m/y', strtotime($wdate));
while($some_value=0)
{
$deduc=$deduc+1;
$some_value--;
}
now I need to subtract $deduc no. of days from $workdate. Please do help.
我需要从存储在动态变量'$ workdate'中的日期中减去天数。 p>
从日期中减去的天数也是动态生成的。 p>
$ workdate = date（'d / m / y'，strtotime（$ wdate））; // $ wdate是从日期选择器中选择并从上一页传递的日期。
code> pre>
我有一个名为'$ deduc'的变量，其值是动态生成的。 假设$ deduc = 2现在我需要做： p>
$ workdate- $ deduc =？
$ workdate = date（'d / m / y'，strtotime （$ wdate））;
而（$ some_value = 0）
{
$ deduc = $ deduc + 1;
$ some_value - ;
}
code> pre >
现在我需要减去$ deduc no。 来自$ workdate的日子。 请帮忙。 p>
div>
答
Just create a DateTime object with DateTime::createFromFormat() and modify() your date, e.g.
$date = DateTime::createFromFormat("d/m/y", $workdate);
echo $date->modify("- $deduc days")->format('Y-m-d');