我可以使用通用的隐式或显式运算符吗？ C＃

问题描述：

我如何更改以下语句，使其接受任何类型而不是长？现在这里是catch，如果没有构造函数，我不想编译它。因此，如果这是一个字符串的构造函数，long和double，但是没有bool，我如何让这一行支持所有这些支持类型？

How do i change the following statement so it accepts any type instead of long? Now here is the catch, if there is no constructor i dont want it compiling. So if theres a constructor for string, long and double but no bool how do i have this one line work for all of these support types?

ATM我刚刚复制粘贴它但我不想这样做，如果我有20种类型（如任务可能微不足道）

ATM i just copied pasted it but i wouldnt like doing that if i had 20types (as trivial as the task may be)

public static explicit operator MyClass(long v) { return new MyClass(v); }

答

现在我可以告诉你，问题是不，我们不能，因为：

Now I can tell you that the answer to you question is "No, we can't" because:

用户定义的转换必须转换为封闭类型或从封闭类型转换。

User-defined conversion must convert to or from the enclosing type.

这就是为什么我们不能在这里使用泛型类型。

That's why we can't use generic types here.

public class Order
{
    public string Vender { get; set; }
    public decimal Amount { get; set; }
}

public class AnotherOrder
{
    public string Vender { get; set; }
    public decimal Amount { get; set; }
    public static explicit operator AnotherOrder(Order o)
    {
        //this method can be put in Order or AnotherOrder only
    }
}

我可以使用通用的隐式或显式运算符吗？ C＃

相关推荐