如何在数据库中插入列的新名称
There is a slight problem when I'm creating a new table in phpmyadmin with new field names. I'm using a for loop trying to insert data for the field names. But for some reason I'm getting a error
"You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near '[0] VARCHAR(30)' at line 3".
Here is my code:
include 'simple_html_dom.php';
include ('connection.php');
function getsquad($url, $tablename){
$html = file_get_html($url);
$player = array();
foreach($html->find('td[align=left]') as $element) {
if ($element->children(0)) { // work only when children exists
array_push($player ,$element->children(0)->innertext);
}
}
$length = count($player);
for($i = 0;$i<=$length;$i++){
// Create a MySQL table in the selected database
mysql_query("CREATE TABLE $tablename(
player[$i] VARCHAR(30)")
or die(mysql_error());
}
echo "Table Created!";
}
$Squad = new squad();
$Squad->getsquad('site', 'Players');
?>
I know the first part of my function is working so I don't think it is a PHP error but not 100% sure.
当我在phpmyadmin中使用新的字段名创建新表时,会出现一些小问题。 我正在使用for循环尝试为字段名称插入数据。 但由于某种原因,我收到错误 p>
“您的SQL语法有错误;请查看 对应于您的MySQL服务器版本的手册 正确的语法在第3行使用 ''[0] VARCHAR(30)'附近“。 p> blockquote>
这是我的代码: p> \ n
包含'simple_html_dom.php'; include('connection.php'); 函数getsquad($ url,$ tablename){ $ html = file_get_html($ url) ); $ player = array(); foreach($ html-&gt; find('td [align = left]')as $ element){ if($ element-&gt; children( 0)){//仅在儿童存在时工作 array_push($ player,$ element-&gt; children(0) - &gt; innertext); } } $ length = count($ player ); for($ i = 0; $ i&lt; = $ length; $ i ++){ //在所选数据库中创建一个MySQL表 mysql_query(“CREATE TABLE $ tablename( nplayer [$ i] VARCHAR(30)“) ot die(mysql_error()); } echo”Table Created!“; } $ Squad = new squad(); $ Squad-&gt; getsquad('site','Players'); ?&gt; code> pre>
我知道我的函数的第一部分正在工作,所以我认为它不是PHP错误,但不是100%确定。 p> div>
You forgot the $
before player. The right way is:
mysql_query("CREATE TABLE $tablename($player[$i] VARCHAR(30)") or die(mysql_error());
update: And as user876345 said, you forget to close the parentheses. So, the code should be:
mysql_query(" CREATE TABLE $tablename( $player[$i] VARCHAR(30) ) ") or die(mysql_error());
You have missed to close the )
at the end of the query and also missed $
in player
variable
CREATE TABLE $tablename( $player[$i] VARCHAR(30) )
Your code should be like:
mysql_query("CREATE TABLE $tablename($player[$i] VARCHAR(30)") or die(mysql_error());