如何匹配数组中的特定值

问题描述：

Im trying to match the array value. how can i match the below code ?

$os = array("CATEGORY=OS", "SYSTEM_NAME like '%A001%'", "CATEGORY=DB");
if (in_array("CATEGORY", $os)) {
    echo "Got it";
}

I need to match the CATEGORY in array how can i do that ?

Edit 2

where (CATEGORY = 'OS' AND SYSTEM_NAME like '%A001%' AND CATEGORY = 'DB' AND SYSTEM_NAME like '%A001%')

I have query something like this i need to replace the AND as OR before category occrence

Expected Output

where (CATEGORY = 'OS' AND SYSTEM_NAME like '%A001%' OR CATEGORY = 'DB' AND SYSTEM_NAME like '%A001%')

我试图匹配数组值。我如何匹配以下代码？ p>

  $ os = array（“CATEGORY = OS”，“SYSTEM_NAME like'％A001％'”，“CATEGORY = DB”）;  
if（in_array（“CATEGORY”，$ os））{
 echo“得到它”; 
} 
  code>  pre> 
 
 我需要匹配 数组中的CATEGORY  code>我该怎么做？ p> 
 
 
 编辑2  strong>  p> 
 
 
  where（CATEGORY  ='OS'和SYSTEM_NAME喜欢'％A001％'和CATEGORY ='DB'和SYSTEM_NAME喜欢'％A001％'）
  code>  pre> 
 
 我有这样的查询 我需要在类别occrence之前将 AND  code>替换为 OR  code>  p> 
 
 
 预期输出 strong>  p> \  n 
 
 其中（CATEGORY ='OS'和SYSTEM_NAME喜欢'％A001％'或CATEGORY ='DB'和SYSTEM_NAME喜欢'％A001％'）
  code>  pre> \  n  div>

答

use this preg_grep() php function

$os = array("CATEGORY=OS", "SYSTEM_NAME like '%A001%'", "CATEGORY=DB");
if (preg_grep("/CATEGORY/", $os)) {
   echo "Got it";
}

For more reference see this

如何匹配数组中的特定值

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