如何使用cURL请求返回的数据？

问题描述：

I am passing an array for a php page to test but I can not get the data!

$data = array(
              "user_id" => $login->id,
              "discount_id" => $discount,
              "product_id" => $product_id->id,
              "date_payment" => $test->id
            );

$fields_string = http_build_query($data);

$url = "http://localhost/dev/felipe/request-checkout.php";

$ch = curl_init();
curl_setopt($ch,CURLOPT_URL,$url);
curl_setopt($ch,CURLOPT_RETURNTRANSFER, TRUE);
curl_setopt($ch,CURLOPT_POST, 1);
curl_setopt($ch,CURLOPT_POSTFIELDS,$fields_string);

$result = json_decode(curl_exec($ch));
curl_close($ch);

page.php:

extract($_POST);

$user_id =  $_POST['user_id']; 
$discount_id =  $_POST['discount_id'];
$product_id =  $_POST['product_id'];
$data_payment =  $_POST['date_payment'];


echo $user_id . ' - ' . $discount_id . ' - ' . $product_id . ' - ' . $data_payment;

show null in $result in cURL. what I'm missing? how do I use the data and have a response which I did cURL?

我传递一个数组用于测试php页面，但我无法获取数据！ p> \ n

  $ data = array（
“user_id”=＆gt; $ login-＆gt; id，
“discount_id”=＆gt; $ discount，
“product_id”=＆gt; $ product_id  - ＆gt; id，
“date_payment”=＆gt; $ test-＆gt; id 
）; 
 
 $ fields_string = http_build_query（$ data）; 
 
 $ url =“http：// localhost /  dev / felipe / request-checkout.php“; 
 
 $ ch = curl_init（）; 
curl_setopt（$ ch，CURLOPT_URL，$ url）; 
curl_setopt（$ ch，CURLOPT_RETURNTRANSFER，TRUE）; 
curl_setopt（$ ch  ，CURLOPT_POST，1）; 
curl_setopt（$ ch，CURLOPT_POSTFIELDS，$ fields_string）; 
 
 $ result = json_decode（curl_exec（$ ch））; 
curl_close（$ ch）; 
  code>  pre  > 
 
  page.php： p> 
 
 
  extract（$ _ POST）; 
 
 $ user_id = $ _POST ['user_id'];  
 $ discount_id = $ _POST ['discount_id']; 
 $ product_id = $ _POST ['product_id']; 
 $ data_payment = $ _POST ['date_payment']; 
 
 
echo $ user_id。  ' - '。  $ discount_id。  ' - '。  $ product_id。  ' - '。  $ data_payment; 
  code>  pre> 
 
 在cURL的$ result中显示null。 我错过了什么？ 我如何使用数据并得到我做过cURL的响应？ p> 
  div>

答

curl_exec($ch) returns string in this format: "1 - 2 - 3 - 4".

When you try to run json_decode() on this string, it returns null because this is not correct json format.

Instead of the echo $user_id . ' - ' . $discount_id . ' - ' . $product_id . ' - ' . $data_payment;, you can endode an array/object to json string:

echo json_encode($_POST);

如何使用cURL请求返回的数据？

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