尝试使用另一个php文件中的函数时出现PHP致命错误

问题描述：

I have looked through some of the other questions on here about including variables from another php file but I've had no luck.

I am trying to include the return of a function in my <title></title>

randomtitle.php

function generateRandomString($length = 10) {
    $characters = '0123456789abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ';
    $charactersLength = strlen($characters);
    $randomString = '';
    for ($i = 0; $i < $length; $i++) {
        $randomString .= $characters[rand(0, $charactersLength - 1)];
    }
    return $randomString;
}

Here is my index.php

index.php

<!DOCTYPE html>
<html>
<head>
    <?php require_once('randomtitle.php'); ?>
    <title><?php echo generateRandomString(); ?></title>
</head>
<body>
</body>
</html>

I get a fatal error Call to undefined function generateRandomString(). Also the actual randomtitle.php file gets displayed in the body of my index.php.

答

Your randomtitle file is missing the <?php ... ?> tags. Without that, PHP will NEVER execute the code within, and treat everything as plain output.

Remember that there is no such thing as a "php script". There are only files with <?php ... ?> code blocks within.

答

Did you have <?php ?> in your randomtitle.php file ?

答

My guess is the problem is one of these:

You're missing the PHP opening tag in randomtitle.php
There's a typo (which I couldn't find)
The route for the require_once is wrong

尝试使用另一个php文件中的函数时出现PHP致命错误

相关推荐