如何用PHP从嵌套的json中读取值？

问题描述：

My cookie's value is JSON format string like this

{
    "_id":{
        "$oid":"5347d81c3e9b2ace058b4567"
    },
    "employee_id":{
        "$oid":"534ae3933e9b2a8f058b4568"
    },
    // some more data
} // it's from mongolab

In my PHP code when trying to get employee_id as result I get only "{"

Here is PHP code

if(isset($_COOKIE['remember_me'])){
    echo($_COOKIE['remember_me']['employee_id']);
}

but if I do echo($_COOKIE['remember_me']) I get as result this`

{"employee_id":{"$id":"5347d81c3e9b2ace058b4567"},"serial_number":"po9TsUdAK6nO6yFdSRyGcpSH7mqU6m+G","cookie_code":"YvfnP6\/PdDG8xhZRkEky1lKvS4n+AUom","hostname":"Titus","user_agent":"Mozilla\/5.0 (X11; Ubuntu; Linux x86_64; rv:28.0) Gecko\/20100101 Firefox\/28.0","user_ip":"127.0.0.1","last_used":false,"_id":{"$id":"534ae3933e9b2a8f058b4568"}}

so I do something wrong, but I'm not experienced enough to find my mistake. Please help, how get employee_id?

我的cookie的值是这样的JSON格式字符串 p>

  {  
“_id”：{
“$ oid”：“5347d81c3e9b2ace058b4567”
}，
“employee_id”：{
“$ oid”：“534ae3933e9b2a8f058b4568”
}，
 //更多数据\  n} //来自mongolab 
  code>  pre> 
 
 在我的PHP代码中，当我尝试获取 employee_id  code>时，我只得到“{”  p> 
 
 
这是PHP代码 p> 
 
 

  if（isset（$ _ COOKIE ['remember_me']））{
 echo（$ _ COOKIE ['remember_me  ''['employee_id']）; 
} 
  code>  pre> 
 
 但如果我执行 echo（$ _ COOKIE ['remember_me']） code> 我得到结果这个` p> 
 
 
  {“employee_id”：{“$ id”：“5347d81c3e9b2ace058b4567”}，“serial_number”：“po9TsUdAK6nO6yFdSRyGcpSH7mqU6m + G”，“cookie_code”：  “YvfnP6 \ / PdDG8xhZRkEky1lKvS4n + AUom”，“hostname”：“Titus”，“user_agent”：“Mozilla \ /5.0（X11; Ubuntu; Linux x86_64; rv：28.0）Gecko \ / 20100101 Firefox \ /28.0”，“user_ip  “：” 127.0.0.1" ， “last_used”：假， “_ ID”：{ “$标识”：“534ae3933e9b2a8f058b4  568“}} 
  code>  pre> 
 
 所以我做错了什么，但我没有足够的经验来发现我的错误。 请帮忙，如何获取 employee_id  code>？   p> 
  div>

答

You can use json_decode to convert a JSON string to an array.

In your case:

$rememberMe = json_decode($_COOKIE['remember_me'], true); // When the second parameter is true, json_decode will return an associative array.
$employeeId = $rememberMe['employee_id']['$id'];

In other words, right now the cookie is just a string. You need to convert it to an array using json_decode.

答

you need to decode the json

$obj = json_decode($_COOKIE['remember_me']);
print $obj->{'employee_id'};

http://www.php.net/manual/en/function.json-decode.php

如何用PHP从嵌套的json中读取值？

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