警告:函数的隐式声明-为什么我的代码仍然可以工作?

我经历了以下线程:

• 警告:函数的隐式声明
• C UNIX中的隐式函数声明

可能我的问题已链接.但是，尽管他们提供了在使用函数之前声明函数原型的解决方案，但我想探索一下函数名称不匹配时会发生什么.在我的测试中，它仍然可以正常工作.

Possibly my issue is linked. But while they offer the solution that the function prototype should be declared before the function is used, I wanted to explore what happens when the function name is not matching. In my test, it still works fine.

主C文件

#include "node.h"
int main(){
    nd *head=NULL;
    nd *tail=NULL;

    create_node(&head, &tail, 10);
    create_node(&head, &tail, 20);
    create_node(&head, &tail, 15);
    create_node(&head, &tail, 35);
    create_node(&head, &tail, 5);
    create_node(&head, &tail, 25);
    print_list(head, tail);
    create_node(&head, &tail, 55);
    create_node(&head, &tail, 52);
    create_node(&head, &tail, 125);

    printf("%d\n",tail->data);
    printf("%d\n",head->data);
    print_list(head, tail);
    return 0;
}

node.h 文件

node.h file

#ifndef NODE_H
#define NODE_H

#include<stdio.h>
#include<stdlib.h>

typedef struct node{
    int data;
    struct node *next;
    struct node *prev;
}nd;

void insert_node(nd **head, nd **tail, int data);

void print_list(nd *head, nd *tail);

#endif

node.c 文件

node.c file

#include "node.h"
void create_node(nd **head, nd **tail, int d){

    nd *temp=(nd *) malloc(sizeof(nd));
    temp->data=d;
    temp->next=NULL;
    temp->prev=NULL;
    /* Start of the Queue.              */
    if(*head==NULL && *tail==NULL){
        *head=temp;
        *tail=temp;
    }
    /* Linking with tail of the Queue.              */
    else if((*tail)->next==NULL){
        (*tail)->next=temp;
        temp->prev=*tail;
        *head=temp;
    }
    /* Adding remaining elements of the Queue.      */
    else{
        (*head)->next=temp;
        temp->prev=*head;
        *head=temp;
    }
}

void print_list(nd *head, nd *tail){
    if(NULL==head){
        printf("Queue is empty\n");
    }
    else{
        printf("Printing the list\n");
        nd *temp;
        for(temp=tail;temp!=NULL;temp=temp->next){
            printf("%d ",temp->data);
        }
        printf("\n");
    }
}

输出

Printing the list
10 20 15 35 5 25 
10
125
Printing the list
10 20 15 35 5 25 55 52 125 

在 node.h 中声明的函数的名称为 insert_node ，而在node.c中则为 create_node .有人可以分享一些关于它为什么运行的见解吗?但是它会发出警告:

The name of the function declared in the node.h is insert_node whereas in node.c it is create_node. Can someone share some insight on why is it running? It throws a warning though:

警告:函数的隐式声明

Warning: implicit declaration of function