由列的内容排序矩阵或二维数组
我在寻找一些帮助code到一列的内容矩阵的内容进行分类，但保持在同一行的数据...我会尽量展示一个例子：
I'm looking for some help with the code to sort a matrix content by the content of one column, but keeping the data of the same row... I will try to show an example:
最初的矩阵是：
正如你可以看到，第一列是位置，第二个是名字，第三是一个假想的ID，和第四个是人的年龄。
As you can see, the first column is the position, second is the name, third is an imaginary ID, and fourth is the age of the person.
这是一个String数组，所以数值数据使用将String.valueOf（数字）转换;
This is a String array, so numerical data is converted using String.valueOf(number);
现在，我想获得帮助与code到每一行进行排序，按任何列的内容。
Now, I would like to get help with the code to sort each row, by the content of any column.
例如，由名字列排序行，应该是这样的：
For example, rows sorted by the names column, should be something like:
现在，由ID列排序行，应该是这样的：
Now, rows sorted by the ID column, should be something like:
正如你所看到的，完整的行，很感动，而不是仅仅在单个列的项目。
As you can see, the complete row was moved, instead of just the items in a single column.
也许有人能帮助我吗？先谢谢了。
May someone help me? Thanks in advance.
下面是一个使用比较器和集合的快速解决方案。一切都应该是自我解释。每一个字段是一个字符串，但你可以很容易地使用整数为好。希望你觉得它有用。
Here's a quick solution using Comparator and Collections. Everything it should be self explanatory. Every field is a String, but you could easily use integer as well. Hope you find it useful.
import java.util.ArrayList;
import java.util.Collections;
import java.util.Comparator;
import java.util.List;
public class MatrixCompare {
public static void main(String[] args) {
List<Contact> contacts = new ArrayList<Contact>();
contacts.add(new Contact("1", "John", "456456", "35"));
contacts.add(new Contact("2", "Jack", "123123", "20"));
contacts.add(new Contact("3", "Mary", "234234", "24"));
contacts.add(new Contact("4", "Jane", "345345", "18"));
System.out.println("Initial List\n");
printContacts(contacts);
System.out.println("\n\nSorted by Id\n");
Collections.sort(contacts, new SortById());
printContacts(contacts);
System.out.println("\n\nSorted by Name\n");
Collections.sort(contacts, new SortByName());
printContacts(contacts);
System.out.println("\n\nSorted by Person Id\n");
Collections.sort(contacts, new SortByPersonId());
printContacts(contacts);
System.out.println("\n\nSorted by Age\n");
Collections.sort(contacts, new SortByAge());
printContacts(contacts);
}
private static void printContacts(List<Contact> contacts) {
for (int i=0; i<contacts.size(); i++) {
System.out.println(contacts.get(i).id + " - " + contacts.get(i).name + " - " +
contacts.get(i).getPersonId() + " - " + contacts.get(i).getAge());
}
}
private static class Contact {
String id;
String name;
String personId;
String age;
public Contact(String id, String name, String personId, String age) {
this.id = id;
this.name = name;
this.personId = personId;
this.age = age;
}
public String getId() {
return id;
}
public String getName() {
return name;
}
public String getPersonId() {
return personId;
}
public String getAge() {
return age;
}
}
private static class SortById implements Comparator<Contact> {
@Override
public int compare(Contact o1, Contact o2) {
String name1 = o1.getId();
String name2 = o2.getId();
return name1.compareTo(name2);
}
}
private static class SortByName implements Comparator<Contact> {
@Override
public int compare(Contact o1, Contact o2) {
String name1 = o1.getName();
String name2 = o2.getName();
return name1.compareTo(name2);
}
}
private static class SortByPersonId implements Comparator<Contact> {
@Override
public int compare(Contact o1, Contact o2) {
String name1 = o1.getPersonId();
String name2 = o2.getPersonId();
return name1.compareTo(name2);
}
}
private static class SortByAge implements Comparator<Contact> {
@Override
public int compare(Contact o1, Contact o2) {
String name1 = o1.getAge();
String name2 = o2.getAge();
return name1.compareTo(name2);
}
}
}