用awk删除空白

问题描述：

我在形式的文件：

Firstname LastName; 123-4567; Job Title
    Firstname LastName;   123-4567;      Job Title
Firstname LastName;      123-4567; Job Title
...

我想使用awk来解析该文件由成makedbm的读取的形式（以使自定义NIS映射）。字段分隔符是一个分号。我需要能够从每个字段在每一行中删除所有前导空格，但留下的空间在名称字段和标题字段。谢谢你。

I am trying to use awk to parse the file into a form readable by makedbm (to make a custom NIS map). Field separator is a semicolon. I need to be able to remove all leading whitespace from each field on each line, but leave the spaces in the name field and the title field. Thanks.

答

如果你想删除的 来自各个领域的前导空格 并保持 中的姓名和职位字段之间的空间 ，然后你可以做这样的事情 -

If you wish to remove leading space from all fields and keep the space in between the Names and Job title fields then you can do something like this -

awk -F";" -v OFS=";" '{for (i=1;i<=NF;i++) gsub (/^ */,"",$i);print}' INPUT_FILE

测试：

[jaypal:~/Temp] cat file
Firstname LastName; 123-4567; Job Title
    Firstname LastName;   123-4567;      Job Title
Firstname LastName;      123-4567; Job Title

[jaypal:~/Temp] awk -F";" -v OFS=";" '{for (i=1;i<=NF;i++) gsub (/^ */,"",$i);print}' file
Firstname LastName;123-4567;Job Title
Firstname LastName;123-4567;Job Title
Firstname LastName;123-4567;Job Title

用awk删除空白

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