表达式删除两个相似的字符和其他尾随字符

问题描述：

I have a php reg expression that removes any special character from any string and replaces the character with a hyphen. The problem is that if there are two special characters following each other, I get two hyphens. for example if I type the text test@hhh%^ I get test-hhh-- or if I type test@hhh%^kkk I get test-hhh--kkk. I want my expression to give me test-hhh. I want to remove two similar hyphens following each other plus any trailing hyphens in the string. My code is here

$slug = preg_replace('/[^a-zA-Z0-9]/', '-', $slug);

我有一个php reg表达式，可以从任何字符串中删除任何特殊字符，并用连字符替换该字符。问题是，如果彼此之后有两个特殊字符，我会得到两个连字符。例如，如果我输入文本test @hhh％^ code>我得到 test-hhh - code>或者如果我输入 test @hhh％^ kkk code> 我得到 test-hhh - kkk code>。我希望我的表达能给我 test-hhh code>。我想删除两个相似的连字符以及字符串中的任何尾随连字符。我的代码在这里 p>

  $ slug = preg_replace（'/ [^ a-zA-Z0-9] /'，' - '，$ slug）; 
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答

First apply this regex to your string:

$slug = preg_replace('#-{2,}#', '-', $slug);

Secondly you apply a right trim (or a regular one) with a hyphen character as an extra argument.

$slug = trim($slug, '-');

答

You can find useful info here http://www.regular-expressions.info/repeat.html, basically you need to specify a repetition modifier.

表达式删除两个相似的字符和其他尾随字符

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