从PHP中的JSON解码数据中提取FIRST结果
问题描述：
I have a script:
$json_url = "https://blockchain.info/ticker";
$json = file_get_contents($json_url);
$json=str_replace('},
]',"}
]",$json);
$data = json_decode($json);
echo "$" . ($data->USD->last);
This works perfect!
Now I have a second version of this:
$json_url3 = "https://blockchain.info/da/unconfirmed-transactions?format=json";
$json3 = file_get_contents($json_url3);
$json3=str_replace('},
]',"}
]",$json3);
$data3 = json_decode($json3);
echo "Latest hash: " . ($data3->txs->hash) . "<br>";
Why does the send script not work? I have a $json2 running without any issues with another API call as well.
我有一个脚本： p>
$ json_url =“https ：//blockchain.info/ticker“;
$ json = file_get_contents（$ json_url）;
$ json = str_replace（'}，
]'，”}
]“，$ json） ;
$ data = json_decode（$ json）;
echo“$”。 （$ data-＆gt; USD-＆gt; last）;
code> pre>
这很完美！ p>
现在我有一秒钟 版本： p>
$ json_url3 =“https://blockchain.info/da/unconfirmed-transactions?format=json";
$json3 = file_get_contents（$ json_url3 ）;
$ json3 = str_replace（'}，
]'，“}
]”，$ json3）;
$ data3 = json_decode（$ json3）;
echo“Latest hash：” 。 （$ data3-＆gt; txs-＆gt;哈希）。 “＆lt; br＆gt;”;
code> pre>
为什么发送脚本不起作用？ 我运行了 $ json2 code>，没有任何其他API调用问题。 p>
div>
答
Variable txs is an array of objects.
Your last line should be written as:
echo "Latest hash: " . ($data3->txs[0]->hash) . "<br>";
It outputs:
Latest hash: fd37b1ddfbe08d485a62bb3aeb7c9088e7dd3a352ac9e9e8eb6f170a9b4210cd
答
This code worked :)
$json_url3 = "https://blockchain.info/da/unconfirmed-transactions?format=json";
$json3 = file_get_contents($json_url3);
$json3=str_replace('},
]',"}
]",$json3);
$data3 = json_decode($json3);
echo "Latest hash: " . ($data3->txs[0]->hash) . "<br>";
txs[0]
I assume the issue was that there is more than 1(one) element in the array