在Laravel 4中将2个参数从路由传递给控制器

问题描述：

Route

Route::get('/site/{site_name_en}/{id}', array(
    'as' => 'profile-site',
    'uses' => 'ProfileController@site'
));

Controller

class ProfileController extends BaseController{

    public function site($id, $site_name_en){
        $site = Site::where('id', '=', $id)
            ->where('site_name_en', '=', $site_name_en);

        if($site->count()){
            $site = $site->first();
            return View::make('profile.site')
                ->with('site', $site);
        }
        return App::abort(404);
    }
}

What I'm trying to achieve is: that when I visit the following URL www.domain.com/site/abc/123456, it will shown the correct page based on the parameters. Is the where clause correct? (because I couldn't retrieve the value)

路线 strong> p>

 路线：  ：get（'/ site / {site_name_en} / {id}'，array（
'as'=＆gt;'profile-site'，
'使用'=＆gt;'ProfileController @ site'
））;  
  code>  pre> 
 
  控制器 strong>  p> 
 
 
 类ProfileController扩展BaseController {
 
公共函数 site（$ id，$ site_name_en）{
 $ site = Site :: where（'id'，'='，$ id）
  - ＆gt; where（'site_name_en'，'='，$ site_name_en）; \  n 
 if（$ site-＆gt; count（））{
 $ site = $ site-＆gt; first（）; 
返回View :: make（'profile.site'）
  - ＆gt; with（  'site'，$ site）; 
} 
返回App :: abort（404）; 
} 
} 
  code>  pre> 
 
 我正在尝试 实现的是：当我访问以下URL  www.domain.com/site/abc/123456  code>时，它将根据参数显示正确的页面。   where  code>子句是否正确？  （因为我无法检索该值） p> 
  div>

答

Your route

Route::get('/site/{site_name_en}/{id}',

says the 1st parameter is site name, the second the id, but your controller function has the arguments swapped. You should call it:

public function site($site_name_en, $id){
   // rest of code
}

parameters are automatically passed down in the order they are defined by the route, and are not recognized by the variable name (IIRC).

As for the rest of your function I can't really tell if you're doing right or not, but I can suggest this:

$site = Site::where('id', '=', $id)
            ->where('site_name_en', '=', $site_name_en)
            ->first();
if($site){
   return View::make('profile.site');
}
return App::abort(404);

Alternatively, you could use firstOrFail(), which throws a ModelNotFoundException if the record is not found that you can catch with App::error() for example (an implementation is outlined in the manual)

在Laravel 4中将2个参数从路由传递给控制器

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