使用C ++中的标签进行静态结构初始化

我已经在*上搜索了答案，但是找不到相关的东西.

I've searched * for an answer but I cannot get something relevant.

我试图通过指定初始值来初始化具有初始值的静态结构实例，但是在编译时出现错误:

I'm trying to initialize a static structure instance with initial values by specifying their tags, but I get an error at compilation time:

src/version.cpp:10: error: expected primary-expression before ‘.’ token

代码如下:

// h
typedef struct
{
    int lots_of_ints;
    /* ... lots of other members */
    const char *build_date;
    const char *build_version;
} infos;

错误代码:

// C

static const char *version_date = VERSION_DATE;
static const char *version_rev  = VERSION_REVISION;

static const infos s_infos =
{
   .build_date    = version_date, // why is this wrong? it works in C!
   .build_version = version_rev
};

const infos *get_info()
{
    return &s_infos;
}

因此，基本思想是绕过其他成员"初始化，而仅设置相关的build_date和build_version值. 这曾经可以在C语言中使用，但我不知道为什么它不能在C ++中使用.

So the basic idea is to bypass the "other members" initialization and only set the relevant build_date and build_version values. This used to work in C, but I can't figure out why it won't work in C++.

有什么想法吗?

修改:

我意识到这段代码看起来像简单的C，实际上是这样.整个项目都是C ++，因此我必须使用C ++文件扩展名来防止makefile依赖关系混乱(%.o: %.cpp)

I realize this code looks like simple C, and it actually is. The whole project is in C++ so I have to use C++ file extensions to prevent the makefile dependency mess ( %.o: %.cpp )