这是一道简短函数题：输入年月日要求输出这是该年第几天？我写的中间代码为什么不执行，求大手指点迷津。

 #include <stdio.h>
#include <stdlib.h>

int calculatedDays(int year,int month,int day);
void main()
{
    int year,month,day;
    scanf("%d %d %d",&year,&month,&day);
    calculatedDays(year,month,day);
    system("pause");
}

int calculatedDays(int year,int month,int day)
{
    int leap,totaldays;
    if((year%4==0&&year%100!=0)||(year%400==0))
        leap=1;
    else
        leap=0;

    if(leap==1)
    {
        if(month==1)
            totaldays=day;
        else if(month==2)
            totaldays=31+day;
        else if(month==3)
            totaldays=31+29+day;
        else if(month==4)
            totaldays=31+29+31+day;
        else if(month==5)
            totaldays=31+29+31+30+day;
        else if(month==6)
            totaldays=31+29+31+30+31+day;
        else if(month==7)
            totaldays=31+29+31+30+31+30+day;
        else if(month==8)
            totaldays=31+29+31+30+31+30+31+day;
        else if(month==9)
            totaldays=31+29+31+30+31+30+31+31+day;
        else if(month==10)
            totaldays=31+29+31+30+31+30+31+31+30+day;
        else if(month==11)
            totaldays=31+29+31+30+31+30+31+31+30+31+day;
        else
            totaldays=31+29+31+30+31+30+31+31+30+31+30+day;
    }
    else
    {
        if(month==1)
            totaldays=day;
        else if(month==2)
            totaldays=31+day;
        else if(month==3)
            totaldays=31+28+day;
        else if(month==4)
            totaldays=31+28+31+day;
        else if(month==5)
            totaldays=31+28+31+30+day;
        else if(month==6)
            totaldays=31+28+31+30+31+day;
        else if(month==7)
            totaldays=31+28+31+30+31+30+day;
        else if(month==8)
            totaldays=31+28+31+30+31+30+31+day;
        else if(month==9)
            totaldays=31+28+31+30+31+30+31+31+day;
        else if(month==10)
            totaldays=31+28+31+30+31+30+31+31+30+day;
        else if(month==11)
            totaldays=31+28+31+30+31+30+31+31+30+31+day;
        else
            totaldays=31+28+31+30+31+30+31+31+30+31+30+day;
    }
    return(printf("该日是该年的第:%4d天\n",totaldays));
}

自己编的函数得先声明，在 main 函数前 加上 int calculatedDays(int year,int month,int day);

什么不执行，我怎么感觉应该把while改成if呢？

 void main()
{int calculatedDays(int year,int month,int day);
int year,month,day;
scanf("%4d,%4d,%4d\n",&year,&month,&day);
calculatedDays(year,month,day);
system("pause");
}

改成下面试试

int calculatedDays(int year,int month,int day);
void main()
{
int year,month,day;
scanf("%4d,%4d,%4d\n",&year,&month,&day);
calculatedDays(year,month,day);
system("pause");
} 

 #include <stdio.h>


int clu_day(int y,int m,int d);
int main()
{
      int sum=0;
      while(1)
      {
      int year=0,mouth=0,day=0;

      printf("璇疯緭鍏ュ勾鏈堟棩鐨勪俊鎭€併€乗n");
      scanf("%d %d %d",&year,&mouth,&day);

      sum=clu_day(year,mouth,day);
      printf("%d鏄?dyear%dmouth%dday\n",sum,year,mouth,day);
      }
      return 0;
}

int clu_day(int y,int m,int d)
{
      int sum=0;
      int feb=0;

      if(((y%4)==0&&(y%100)!=0)||(y%400==0))
      {
        feb=29;
      }
      else
      {
        feb=28;
      }
      if(m==1)
      {
        sum=d;
    //    return sum;
      }
      if(m==2)
      {

        sum=31+d;
      //    return sum; 

      }
      if(m==3)
      {

          sum=31+feb+d;
    //    return sum;

      }
      if(m==4)
      {

        sum=31+feb+31+d;
      //    return sum; 

      }
      if(m==5)
      {

        sum=31+feb+31+30+d;
        //  return sum; 

      }
      if(m==6)
      {

        sum=31+feb+31+30+31+d;
          //return sum; 

      }
      if(m==7)
      {

        sum=31+feb+31+30+31+30+d;
         // return sum; 

      }
      if(m==8)
      {

        sum=31+feb+31+30+31+30+31+d;
         /// return sum;    

      }
      if(m==9)
      {

        sum=31+feb+31+30+31+30+31+31+d;
         /// return sum;    

      }
      if(m==10)
      {

        sum=31+feb+31+30+31+30+31+31+30+d;
         // return sum; 

      }
      if(m==11)
      {

        sum=31+feb+31+30+31+30+31+31+30+31+d;
         // return sum; 

      }
      if(m==12)
      {

        sum=31+feb+31+30+31+30+31+31+30+31+30+d;
         // return sum; 

      }
      return sum;

}

上面乱码是ubantu换到source insight 上面出现的 不影响结果

讲真的，这代码。。。为啥不用一个数组存月份，再来一个for循环呢，几行代码就搞定了啊