在php中修剪超过需要的URL

问题描述：

I am entering URL's into my database and i was getting all possible entries

I have the following code that takes the http:// or http or www .com .co.uk away

but the problem is this

when I enter a site like hat.com its taking the 'h' away this happens with t, p, w, and if its .co.uk it only removes the .uk

$new = rtrim($url, "/");

$reverse = strrev( $new );
$new = rtrim($reverse, ".www");
$new = rtrim($reverse, "//:ptth");
$new = rtrim($reverse, ".www//:ptth");
$new = rtrim($reverse, "//:sptth");
$new = rtrim($reverse, ".www//:sptth");
$url = strrev( $new );

Whats have I missed and what would I have to add?

我正在输入URL到我的数据库中，我得到了所有可能的条目 p>

我有以下代码，它采用http：// code>或 http code>或 www code> .com code> .co.uk code> away p>

但问题是这个 p>


当我进入像hat.com这样的网站时 't，p，w会发生这种情况，如果它的.co.uk它只删除.uk  p> 
 
 
  $ new = rtrim（$ url，“/”）  ; 
 
 $ reverse = strrev（$ new）; 
 $ new = rtrim（$ reverse，“。www”）; 
 $ new = rtrim（$ reverse，“//：ptth”）; 
  $ new = rtrim（$ reverse，“。www //：ptth”）; 
 $ new = rtrim（$ reverse，“//：sptth”）; 
 $ new = rtrim（$ reverse，“。www /  /：sptth“）; 
 $ url = strrev（$ new）; 
  code>  pre> 
 
 我错过了什么，我需要添加什么？ p>  
  div>

答

Using a regular expression will help here:

preg_replace('~(^https?(://(www\.)?)?|\.com$|\.co\.uk$)~', '', $url);

The regular expression used will match:

http, https, http://, https://, http://www., https://www. at the beginning of the string
.com, .co.uk at the end of the string.

See this example:

php> $url = 'https://www.example.com';
'https://www.example.com'
php> preg_replace('~(^https?(://(www\.)?)?|\.com$|\.co\.uk$)~', '', $url);
'example'
php> $url = 'http://hat.com';
'http://hat.com'
php> preg_replace('~(^https?(://(www\.)?)?|\.com$|\.co\.uk$)~', '', $url);
'hat'

在php中修剪超过需要的URL

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