如何获取数组中的值以及如何使用codeigniter在数据库中插入
Here i have one array, in this array i have one more array name studentAbsentId
, now i want insert the studentAbsentId
in database, like here studentAbsentId
2 and studentAbsentId
2 is absent so i need to insert the two rows
My updated code print_r($params);
Array
(
[studentAbsentId] => Array
(
[0] => 2
[1] => 3
)
[schoolId] => 2
[classId] => 1
[sectionId] => 1
[studentAbsentDate] => 2017-04-18
[reg_date] => 2017-04-18 05:20:17
[created_by] => 1
)
Now i want to take only studentAbsentId,how can do?
expected results
2
3
这里我有一个数组,在这个数组中我还有一个数组名 我的更新代码 print_r($ params); strong> p>
blockquote>
现在我只想拿studentAbsentId,该怎么办? p>
预期结果 p>
blockquote>
studentAbsentId code>, 现在我想在数据库中插入
studentAbsentId code>,就像这里
studentAbsentId code> 2和
studentAbsentId code> 2不存在所以我需要插入两行 p >
数组
(
[studentAbsentId] =>数组
(
[0] => 2
[1] => 3
)
[schoolId] => 2
[ classId] => 1
[sectionId] => 1
[studentAbsentDate] => 2017-04-18
[reg_date] => 2017-04-18 05:20:17
[created_by ] => 1
)
code> pre>
2
3
code> pre>
div>
Try this it helps :)
<?php
$params=array(
'studentAbsentId' => array
( 2,3
),
'studentAbsentDate' => '2017-04-18',
'reg_date' => '2017-04-18 04:41:21',
'created_by' => '1',
);
foreach($params['studentAbsentId'] as $ff)
{
$atnEntry = array(
"studentAbsentId" => $ff,
"studentAbsentDate" =>$params['studentAbsentDate'],
"morning" => "1"
);
$this->db->insert("student_absent_list" , $atnEntry);
}
$return = array("status" => "Success" );
echo json_encode($return);
?>
Try this
$test = array('studentAbsentId' => array('2','3'),'studentAbsentDate' => '2017-04-18','reg_date' => '2017-04-18 04:41:21','created_by' => '1');
foreach($test['studentAbsentId'] AS $tet)
{
$array_val = array('studentAbsentId' => $tet,'studentAbsentDate' => $test['studentAbsentDate'],'created_by' => $test['created_by']);
// echo "<pre>";print_r($array_val);
$this->db->insert('table_name',$array_val);
}