如何使用PHP删除字符串中的第7个和第8个到最后一个字符？

问题描述：

I want to remove the the 7th and 8th to last characters in a string.

$string = "Tucson AZ 85718";

I am trying to remove the state abbreviation. I have a bunch of these strings for different zip codes, so I can't just replace "AZ" with ''.

我想删除字符串中的第7个和第8个到最后一个字符。 p>

  $ string =“Tucson AZ 85718”;  
  code>  pre> 
 
 我正在尝试删除州名缩写。 我有一堆这些字符串用于不同的邮政编码，所以我不能只用''代替“AZ”。   p> 
  div>

答

$string = substr($string, 0, -8) . substr($string, -5);

Demo:

php> $string = "Tucson AZ 85718";
php> echo substr($string, 0, -8) . substr($string, -5);
Tucson 85718

A regex would also do the job. This one would remove any 2-uppercase-character string and the space after it:

$string = preg_replace('/\b[A-Z]{2}\b /', '', $string);

答

$string = substr_replace($string, "", -8, 2);

答

not an php regexp expert, but it seems that

$string=preg_replace(" {w{1}} ", " ", $string);

would do the job for you. Should work with variable length city name.:wq

答

Disclaimer: I'm not American and don't know American postal addresses too well!

I would definitely do this with preg_replace or preg_match_all:

$string   = "Tucson AZ 85718"; 

// Don't be mislead by the second [A-Z], this means all uppercase characters
$pattern  = '/^(.+ )([A-Z]{2} )(\d+)$/';
preg_match_all($pattern, $string, $matches);

var_dump($matches);

This'll give you an array that looks like this:

array(4) {
  [0]=>
  array(1) {
    [0]=>
    string(15) "Tucson AZ 85718"
  }
  [1]=>
  array(1) {
    [0]=>
    string(7) "Tucson "
  }
  [2]=>
  array(1) {
    [0]=>
    string(3) "AZ "
  }
  [3]=>
  array(1) {
    [0]=>
    string(5) "85718"
  }
}

...where the 2nd, 3rd and 4th indexes will be the City, State code and Zip code respectively.

Alternatively, you could just strip the prefix with preg_replace:

$string   = "Tucson AZ 85718"; 
$pattern  = '/^(.+ )([A-Z]{2} )(\d+)$/';
$normalised = preg_replace($pattern, '$1$3', $string);

...which will give you "Tucson 85718", where the $1 and $3 in the second argument to preg_replace relate to the first and third blocks in parenthesis in the pattern ((.* ) and (\d{5}) respectively).

Assumptions:

States codes are all caps
Zip codes are all 5 digits

如何使用PHP删除字符串中的第7个和第8个到最后一个字符？

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