PHP - 在无法确定长度时查找并替换两个变量之间的字符串

问题描述：

I'm trying to create a simple PHP find and replace system by looking at all of the images in the HTML and add a simple bit of code at the start and end of the image source. The image source has something like this:

<img src="img/image-file.jpg">

and it should become into this:

<img src="{{media url="wysiwyg/image-file.jpg"}}"

The Find

="img/image-file1.jpg"
="img/file-2.png"
="img/image3.jpg"

Replace With

="{{media url="wysiwyg/image-file.jpg"}}"
="{{media url="wysiwyg/file-2.png"}}"
="{{media url="wysiwyg/image3.jpg"}}"

The solution is most likely simple yet from all of the research that I have done. It only works with one string not a variety of unpredictable strings.

Current Progress

$oldMessage = "img/";
$deletedFormat = '{{media url="wysiwyg/';
$str = file_get_contents('Content Slots/Compilied Code.html');
$str = str_replace("$oldMessage", "$deletedFormat",$str);

The bit I'm stuck at is find the " at the end of the source to add the end of the required code "}}"

我正在尝试通过查看全部创建一个简单的PHP code>查找和替换系统 HTML code>中的图像，并在图像源的开头和结尾添加一些简单的代码。图像源具有以下内容： p>

 ＆lt; img src =“img / image-file.jpg”＆gt; 
  code>  pre> 
  
 它应该变成这样： p> 
 
 
 ＆lt; img src =“{{media url =”wysiwyg / image-file.jpg“}}”  n  code>  pre> 
 
  查找 strong>  p> 
 
 
  =“img / image-file1.jpg”\  n =“img / file-2.png”
 =“img / image3.jpg”
  code>  pre> 
 
  替换为 strong>  p  > 
 
 
  =“{{media url =”wysiwyg / image-file.jpg“}}”
 =“{{media url =”wysiwyg / file-2.png“}}  “
 =”{{media url =“wysiwyg / image3.jpg”}}“
  code>  pre> 
 
 解决方案很可能很简单而且来自所有的研究 我已经做好了。 它只适用于一个字符串而不是各种不可预测的字符串。 p> 
 
 
 当前进度 strong>  p> 
 
 
  $ oldMessage =  “img /”; 
 $ deletedFormat ='{{media url =“wysiwyg /'; 
 $ str = file_get_contents（'Content Slots / Compilied Code.html'）; 
 $ str = str_replace（”$ oldMessage“  ，“$ deletedFormat”，$ str）; 
  code>  pre> 
 
 我坚持的位置是在结尾处找到“ code>  source添加所需代码的结尾“}}” code>  p> 
  div>

答

I don't like to build regular expressions to parse HTML, but it seems that in this case, a regular expression will help you:

$reg = '/=["\']img\/([^"\']*)["\']/';
$src = ['="img/image-file1.jpg"', '="img/file-2.png"', '="img/image3.jpg"'];

foreach ($src as $s) {
    $str = preg_replace($reg, '={{media url="wysiwyg/$1"}}', $s);
    echo "$str
";
}

Here you have an example on Ideone.

To make it works with your content:

$content = file_get_contents('Content Slots/Compilied Code.html');
$reg = '/=["\']img\/([^"\']*)["\']/';
$final = preg_replace($reg, '={{media url="wysiwyg/$1"}}', $content);

Here you have an example on Ideone.

答

In my opinion what you are doing is not the best way this can be done. I would use abstract template for this.

<?php
$content = file_get_contents('Content Slots/Compilied Code.html');
preg_match_all('/=\"img\/(.*?)\"/', $content, $matches);
$finds = $matches[1];
$abstract = '="{{media url="wysiwyg/{filename}"}}"';
$concretes = [];
foreach ($finds as $find) {
    $concretes[] = str_replace("{filename}", $find, $abstract);
}
// $conretes[] will now have all matches formed properly...

Edit:

To return full html use this:

<?php
$content = file_get_contents('Content Slots/Compilied Code.html');
preg_match_all('/=\"img\/(.*)\"/', $content, $matches);
$finds = $matches[1];
$abstract = '="{{media url="wysiwyg/{filename}"}}"';
foreach ($finds as $find) {
    $content = preg_replace('/=\"img\/(.*)\"/', str_replace("{filename}", $find, $abstract), $content, 1); 
}
echo $content;

PHP - 在无法确定长度时查找并替换两个变量之间的字符串

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