字母之间只允许一个空格

问题描述：

I don't know almost anything about regex, but I need to allow only one space between letters, this is what I have done with another questiona and answer, plus random tries with regex101:

/^(\d){1,}(\:[A-Za-z0-9-]+([ a-zA-Z0-9-]+)?)?\:(\d){1,}(?:\.(\d){1,2})?$/m

The fomat should be:

[integer]:[optional label :][integer/decimal]

Example:

12:aaa:12.31
56:a s f:15
34:45.8

I have done some random tries without any success,I'm only able to allow infinite space, could someone help me? I have also looked at others answers, but I couldn't implement in my regex.

Check if error:

    preg_match_all('/^(\d+)(:[A-Z0-9-]+(?: [A-Z0-9-]+)*)?:(\d+(?:\.\d{1,2})?)$/mi', $_POST['ratetable'], $out);
    if($out[0]!=explode("
",$_POST['ratetable'])){
        header('Content-Type: application/json; charset=utf-8');
        echo json_encode(array(0=>'Invalid price table at line: '.implode(", ", array_diff_key(array_flip(explode("
",$_POST['ratetable'])),array_flip($out[0])))));
        exit();
    }

我几乎不知道有关正则表达式的任何内容，但我需要在字母之间只允许一个空格，这就是我已经完成了另一个问题和答案，以及使用regex101的随机尝试： p>

  / ^（\ d）{1，}（\：[A-Za-z0-9  - ] +（[a-zA-Z0-9  - ] +）？）？\：（\ d）{1，}（？：\。（\ d）{1,2}）？$ / m 
   code>  pre> 
 
  fomat应该是： p> 
 
 
  [integer]：[可选标签：] [整数/小数] 
  代码>  PRE> 
 
 示例： p> 
 
 
  12：AAA：12.31 \ N56：ASF：15 \ N34：45.8 
   code>  pre> 
 
 我做了一些随机尝试而没有任何成功，我只能允许无限空间，有人可以帮助我吗？ 我也查看了其他答案，但我无法在我的正则表达式中实现。 p> 
 
 
检查是否有错误： p> 
 
 
  preg_match_all（'  / ^（\ d +）（：[A-Z0-9  - ] +（？：[A-Z0-9  - ] +）*）？:( \ d +（？：\。\ d {1,2}）  ？）$ / mi'，$ _POST ['ratetable']，$ out）; 
 if（$ out [0]！= explode（“
”，$ _ POST ['ratetable']））{
 header  （'Content-Type：application / json; charset = utf-8'）; 
 echo json_encode（array（0 =＆gt;'行无效价格表：'。implode（“，”，array_diff_key（array_flip（explode（  “
”，$ _ POST ['ratetable']）），array_flip（$ out [0]）））））; 
 exit（）; 
} 
  code>  pre>

答

You could make the regex a bit shorter and allow a single space in between each letter like this:

/^(\d+)(:[A-Z0-9-]+(?: [A-Z0-9-]+)*)?:(\d+(?:\.\d{1,2})?)$/gmi

regex101 demo

If you want to capture only the label (and exclude the :) in the capture, you can use this one.

答

You're nearly there:

(?: [a-zA-Z0-9-]+)*

the above would mean: space followed by at least one in the character group; the latter group any number of times, without capturing

答

I think

^\d+:([^:]+:)?\d+(\.\d+)?$

might do it...

It means: <int> + ":" + [label + ":"] + <float> where label can be anything but :.

答

You can use preg_match

$str = 'Another Example String 1_2-3';
echo $str . "<br />
";
if (preg_match('#^(?:[\w-]+ ?)+$#', $str)){
    echo 'Legal format!';
} else {
    echo 'Illegal format!';
}

答

^\d+:([\w\d]+ ?)*:?\d+(\.\d+)?$

Live demo

字母之间只允许一个空格

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