在新的浏览器/窗口上点击提交按钮后打开PHP操作
问题描述:
Good Day, I am trying to make this code run on a new window; Below is my code:
TEST1.PHP
<html><head>
<script>
function submitForm(action)
{
document.getElementById('1').action = action;
document.getElementById('1').submit();
}
</script>
<title>test</title></head><body><form id="1" name="test-1" action="test3.php" method="post">
<input name="fname"><input name="lname"><br>
<input value="Save" name="save" )="" type="submit">
<input value="Nwindow" name="nwindow" onclick="submitForm('test2.php');
window.open='test2.php'" type="submit">
TEST2.PHP
<html><head>
<form id="2" name="test-2" action="test2.php" method="post">
<title>test</title></head><body>
<input name="fname" value="<?php echo $_POST['fname']; ?>">
<input name="lname" value="<?php echo $_POST['lname']; ?>">
<br>
</form>
</body></html>
They both work correctly but what i wanted for nwindow button to perform TEST2.PHP on another window/browser; I tried window open but it is not working.
I am new with javascript so i am not sure it this can be done.
Any help is much appreciated.
Thanks in Advance.
答
Simply use target="_blank"
on your first form.
Read the manual for more info on forms: https://developer.mozilla.org/en-US/docs/Web/HTML/Element/form
EDIT: If you want to only load the new tab for one of the submit buttons, do this:
<form id="myForm" name="test-1" action="test3.php" method="post">
<input name="fname"><input name="lname"><br>
<input value="Save" name="save" type="button" onclick="submitForm('test3.php','_self');">
<input value="Nwindow" name="nwindow" type="button" onclick="submitForm('test2.php','_blank');">
Then in your JS:
function submitForm(action,target)
{
document.getElementById('myForm').target = target
document.getElementById('myForm').action = action;
document.getElementById('myForm').submit();
}