使用DOMxpath或regex删除 ？

问题描述：

I use DOMxpath to remove html tags that have empty text node but to keep   tags,

$xpath = new DOMXPath($dom);

while(($nodeList = $xpath->query('//*[not(text()) and not(node()) and not(self::br)]')) && $nodeList->length > 0) 
{
    foreach ($nodeList as $node) 
    {
        $node->parentNode->removeChild($node);
    }
}

it works perfectly until I came across another problem,

$content = '<p><br/><br/><br/><br/></p>';

How do remove this kind of messy  and? which means I don't want to allow   alone with  but I allow   with proper text like this only,

$content = '<p>first break <br/> second break <br/> the last line</p>';

Is that possible?

Or is it better with a regular expression?

I tried something like this,

$nodeList = $xpath->query("//p[text()=<br\s*\/?>\s*]");
    foreach($nodeList as $node) 
    {
        $node->parentNode->removeChild($node);
    }

but it return this error,

Warning: DOMXPath::query() [domxpath.query]: Invalid expression in...

我使用DOMxpath删除具有空文本节点的html标记但保留＆lt; br /＆gt; code>标签， p>

  $ xpath = new DOMXPath（$ dom）; 
 
while（（$ nodeList = $ xpath-＆gt; query（'// *  [not（text（））and not（node（））and not（self :: br）]'））＆amp;＆amp; $ nodeList-＆gt; length＆gt; 0）
 {
 foreach（$ nodeList as  $ node）
 {
 $ node-＆gt; parentNode-＆gt; removeChild（$ node）; 
} 
} 
  code>  pre> 
 
 它完美无缺 我遇到了另一个问题， p> 
 
 
  $ content ='＆lt; p＆gt;＆lt; br /＆gt;＆lt; br /＆gt;＆lt; br /＆gt;＆lt; br /  ＆GT;＆LT; / p为H.';  
  code>  pre> 
 
 如何删除这种凌乱的＆lt; br /＆gt;  code>和＆lt; p＆gt;  code>？ 这意味着我不想单独使用＆lt; br /＆gt;  code>和＆lt; p＆gt;  code>，但我允许＆lt; br /＆gt;  code  >只有这样的正确文字， p> 
 
 
  $ content ='＆lt; p＆gt; first break＆lt; br /＆gt; 第二次休息＆lt; br /＆gt; 最后一行＆lt; / p＆gt;';  
  code>  pre> 
 
 这可能吗？ p> 
 
 
或者使用正则表达式会更好吗？ p> 
 
  
 
 
  $ nodeList = $ xpath-＆gt; query（“// p [text（）=＆lt; br \ s * \ /？  ＆gt; \ s *]“）; 
 foreach（$ nodeList as $ node）
 {
 $ node-＆gt; parentNode-＆gt; removeChild（$ node）; 
} 
  code>   pre> 
 
 但它返回此错误， p> 
 
 
 警告：DOMXPath :: query（）[domxpath.query]：...中的表达式无效 n  code>  pre> 
  div>

答

You can select the unwanted p using XPath:

"//p[count(*)=count(br) and br and normalize-space(.)='']"

Note to select empty-text nodes shouldn't you better use (?):

"//*[normalize-space(.)='' and not(self::br)]"

This will select any element (but br) whithout text nodes, nodes like:

<p><b/><i/></p>

<p> <br/>   <br/>
</p>

included.

答

You could get rid of them all by simply checking to see that the only things within a paragraph are spaces and   tags: preg_replace("\<p\>(\s|\<br\s*\/\>)*\<\/p\>","",$content);

Broken down:

\<p\>    # Match for <p>
(        # Beginning of a group
  \s       # Match a space character
  |        # or...
  \<br\s*\/\> # match a <br /> tag, with any number (including 0) spaces between the <br and />
)*       # Match this whole group (spaces or <br /> tags) 0 or more times.
\<\/p\>  # Match for </p>

I will mention, however, that unless your HTML is well-formatted (one-line, no strange spaces or paragraph classes, etc), you should not use regex to parse this. If it is, this regex should work just fine.

答

I have almost same situation, i use:

$document->loadHTML(str_replace('<br>', urlencode('<br>'), $string_or_file));

And use urlencode() to change it back for display or inserting to database. Its work for me.

使用DOMxpath或regex删除 ？

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