快速的输入输出功能
#define getcx getchar_unlocked
inline void inp( int &n )//fast input function
{
n=0;
int ch=getcx();int sign=1;
while( ch < '0' || ch > '9' ){if(ch=='-')sign=-1; ch=getcx();}
while( ch >= '0' && ch <= '9' )
n = (n<<3)+(n<<1) + ch-'0', ch=getcx();
n=n*sign;
}
您好我一直在使用输入上述功能在不同的编码比赛,但为什么它快速始终无法理解。我所知道的逻辑,但不知道它的牢度的概念。例如这是什么线做getchar_unlocked的#define getcx。此外,我不知道任何快速输出功能,因此没有任何快速输出功能还可
Hi I have been using the above function for input in various coding contests but was never able to understand why is it fast. I know the logic but don't know the concept of it's fastness. For example what is this line doing "#define getcx getchar_unlocked" . Also I don't know any fast output function so is there any fast output function also
的的#define
使用preprocessor使 getcx
是一个短手功能 getchar_unlocked()
,这是一种非锁定字符阅读功能
The #define
uses the preprocessor to make getcx
be a short-hand for the function getchar_unlocked()
, which is a non-locking character-reading function.
这是一个有点真棒,你已经在多个编码竞赛竞争不理解这个pretty基础件C的。
It's a bit awesome that you've competed in several coding contests without understanding this pretty basic piece of C.
该手册页我联系上面提到 putc_unlocked()
这听起来像pretty同样的事情,但输出。
The manual page I linked to above mentions putc_unlocked()
which sounds like pretty much the same thing but for output.