如何循环依赖<td>在表上 - 网页学习体会

问题描述：

I have problem with looping in table. i want to loop a <td>, when it reach 10 , it build <tr> automatically. Here my code:

$sd=mysql_query("SELECT a.*,b.* FROM surat_jalan a inner join packing_list b on a.id_surat = b.identitas_packing WHERE b.identitas_packing = '$ben[id_surat]' ORDER BY netto_packing ASC"); 
while($pack=mysql_fetch_array($sd)){
    $komapack = number_format($pack['netto_packing'],2);
    echo"<td>$komapack</td>"; 
}

I am stuck on here and don't know what to do but I know how to use mod but " don't know how to loop it.

我在表中循环有问题。我想循环＆lt; td＆gt; code>，当它达到10时，它会自动构建＆lt; tr＆gt; code>。这是我的代码： p>

  $ sd = mysql_query（“SELECT a。*，b。* FROM surat_jalan a aid_surat = b.identitas_packing WHERE b.identitas_packing ='$ ben [id_surat]'内部联接packing_list b'ORDER BY netto_packing  ASC“）;  
while（$ pack = mysql_fetch_array（$ sd））{
 $ komapack = number_format（$ pack ['netto_packing']，2）; 
 echo“＆lt; td＆gt; $ komapack＆lt; / td＆gt;”;  
} 
  code>  pre> 
 
 我被困在这里，不知道该怎么做，但我知道如何使用mod，但“不知道如何循环它 。 p> 
  div>

答

You can use a counter.

$i = 0;
echo "<tr>";
while($pack=mysql_fetch_array($sd)){
    $komapack = number_format($pack['netto_packing'],2);
    echo"<td>$komapack</td>"; 
    $i++;
    if($i % 10 == 0) // check
       echo "</tr><tr>";
}
echo "</tr>";

如何循环依赖在表上

相关推荐