从仅包含URL字符串中的特定单词的文本中获取图像URL

问题描述：

I use preg_match_all to get all images URLs from the text string:

preg_match_all('!http://[^?#]+\.(?:jpe?g|png|gif)!Ui', $text , $matches);

Unfortunately, this time I need to get only images that contains '/bigimage/' inside the initial string.
i.e. $matches array should have only contains image elements like:

  http://x/x/bigimage/x/x.jpg

How could I modify source command to get desired result?

我使用preg_match_all从文本字符串中获取所有图像URL： p>

   preg_match_all（'！http：// [^？＃] + \。（？：jpe？g | png | gif）！Ui'，$ text，$ matches）; 
  code>  pre  > 
 
 
 不幸的是，这次我只需要在初始字符串中只包含'/ bigimage /'的图像。 p>  li> 
 

  ie 
 $ matches数组应该只包含图像元素，如： p>  li> 
  ul> 
 
 
 
   http：/  /x/x/bigimage/x/x.jpg


nn我如何修改源命令以获得所需的结果 ？ li> 
  ul> 
  div>

答

try

(http://(?:\w+/)*bigimage(?:/\w+)*((/\w).(?:jpe?g|png|gif)))

for visualization https://www.debuggex.com/r/22db9byd3cTlIX6f

Change the brackets () or capturing groups according to your need

从仅包含URL字符串中的特定单词的文本中获取图像URL

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