如何获取启动文件路径 GetModuleFileName 如何获取启动文件路径 GetModuleFileName
CString GetExeDirPath() { char fn[MAX_PATH] = {0}; CString strExeDirPath; GetModuleFileName(NULL, strExeDirPath.GetBufferSetLength(MAX_PATH), MAX_PATH);//获取启动路径:"c:UserswhlDesktopExampleDebugExample.exe" CString m_strExeDirPath = strExeDirPath.Left(strExeDirPath.ReverseFind('\'));//获取程序的启动路径: "c:UserswhlDesktopExampleDebug" return m_strExeDirPath; }