HDU 6203 ping ping ping [LCA,贪心,DFS序,BIT(树状数组)]
题目链接:【http://acm.hdu.edu.cn/showproblem.php?pid=6203】
题意 :给出一棵树,如果(a,b)路径上有坏点,那么(a,b)之间不联通,给出一些不联通的点对,然后判断最少有多少个坏点。
题解 :求每个点对的LCA,然后根据LCA的深度排序。从LCA最深的点对开始,如果a或者b点已经有点被标记了,那么continue,否者标记(a,b)LCA的子树每个顶点加1。
#include<Bits/stdc++.h>
using namespace std;
const int maxn = 2e5 + 5;
int N, Q;
int c[maxn], In[maxn], Out[maxn], cnt;
struct Edge
{
int id, next;
Edge(int id = 0, int next = 0): id(id), next(next) {}
} E[maxn << 1]; //双向边
int head[maxn], tot;
void initEdge()
{
memset(c, 0, sizeof(c));
cnt = 0;
for(int i = 0; i <= N; i++) head[i] = -1;
tot = 0;
}
void addEdge(int u, int v)
{
E[tot] = Edge(v, head[u]);
head[u] = tot++;
}
int siz[maxn], top[maxn], dep[maxn], fa[maxn];
int clk;//需要初始化
void DFS1(int u, int p)
{
In[u] = ++cnt;
dep[u] = dep[p] + 1;
fa[u] = p, siz[u] = 1;
for(int k = head[u]; k != -1; k = E[k].next)
{
int id = E[k].id;
if(id == p) continue;
DFS1(id, u);
siz[u] += siz[id];
}
Out[u] = cnt;
}
void DFS2(int u, int p)
{
int son = -1;
for(int k = head[u]; k != -1; k = E[k].next)//找重儿子
{
int id = E[k].id;
if(id == p)continue;
if(son == -1 || siz[id] > siz[son]) son = id;
}
if(son != -1)
{
top[son] = top[u];
DFS2(son, u);
}
for(int k = head[u]; k != -1; k = E[k].next)
{
int id = E[k].id;
if(id == p || id == son)continue;
top[id] = id;
DFS2(id, u);
}
}
int LCA(int x, int y)
{
while(top[x] != top[y])
{
if(dep[top[x]] < dep[top[y]]) swap(x, y);
x = fa[top[x]];
}
if(dep[x] > dep[y]) swap(x, y);
return x;
}
struct node
{
int u, v, lca;
bool operator < (const node &T) const
{
return dep[lca] > dep[T.lca];
}
} qry[50050];
int low_Bit(int x)
{
return x & -x;
}
void update(int x, int val)
{
while(x <= N)
{
c[x] += val;
x += low_Bit(x);
}
}
int get_sum(int x)
{
int ret = 0;
while(x > 0)
{
ret += c[x];
x -= low_Bit(x);
}
return ret;
}
int main()
{
while(~scanf("%d", &N))
{
N++;
initEdge();
for(int i = 1; i <= N - 1; i++)
{
int u, v;
scanf("%d %d", &u, &v);
u++, v++;
addEdge(u, v), addEdge(v, u);
}
DFS1(1, 0),top[1] = 1,DFS2(1, 0);
scanf("%d", &Q);
for(int i = 1; i <= Q; i++)
{
scanf("%d %d", &qry[i].u, &qry[i].v);
qry[i].u++, qry[i].v++;
qry[i].lca = LCA(qry[i].u, qry[i].v);
}
sort(qry + 1, qry + 1 + Q);
int ans = 0;
for(int i = 1; i <= Q; i++)
{
int u = qry[i].lca;
int ret = get_sum(In[qry[i].u]) + get_sum(In[qry[i].v]);
if(ret) continue;
ans++;
update(In[u], 1);
update(Out[u] + 1, -1);
}
printf("%d
", ans);
}
return 0;
}