Python 3：如何在一行代码中比较多个字符串？

问题描述：

我正在尝试在Python 3中选择类别（通过文本界面），我想知道如何比较多个字符串是否不正确，然后沿那是无效的行打印内容选择

I'm trying to make a category select (by text interface) in Python 3, and I was wondering how I can compare if multiple strings are not true, and then print something along the lines of "that is not a valid choice"

    input("what is your category choice?")
    if categoryChoice != "category1", "category 2", "category 3":
    print("not a valid choice")

我不明白让它检查category1，category2，category3等是否为真/假的语法

I don't understand the syntax for having it check if any of category1, category2, category3, etc is true/false

答

在中使用

categoryChoice = input("what is your category choice?")
if categoryChoice not in ("category1", "category 2", "category 3"):
    print("not a valid choice")

http://ideone.com/e6n0Rr

如果您是使用Python 2，您应该真的使用 raw_input 而不是 input 。

By the way, if you're using Python 2, you should really use raw_input instead of input.

Python 3：如何在一行代码中比较多个字符串？

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