我们可以在Codeigniter中的同一视图中使用两个数据库吗？
I want to access data from two different database.
I want to print the records from two database into same view.
Now my first query is from the another database then the second query is from default database. So I get an error that SecondDatabase.tablenmae doesn't exist and actually the table is in default database
So I defined them like this:
$active_group = 'default';
$active_record = TRUE;
$db['default']['hostname'] = 'localhost';
$db['default']['username'] = 'root';
$db['default']['password'] = '';
$db['default']['database'] = 'biz_prov';
$db['default']['dbdriver'] = 'mysql';
$db['default']['dbprefix'] = '';
$db['default']['pconnect'] = TRUE;
$db['default']['db_debug'] = TRUE;
$db['default']['cache_on'] = FALSE;
$db['default']['cachedir'] = '';
$db['default']['char_set'] = 'utf8';
$db['default']['dbcollat'] = 'utf8_general_ci';
$db['default']['swap_pre'] = '';
$db['default']['autoinit'] = TRUE;
$db['default']['stricton'] = FALSE;
$db['bizlms']['hostname'] = 'localhost';
$db['bizlms']['username'] = 'root';
$db['bizlms']['password'] = '';
$db['bizlms']['database'] = 'bizlms';
$db['bizlms']['dbdriver'] = 'mysql';
$db['bizlms']['dbprefix'] = '';
$db['bizlms']['pconnect'] = FALSE;
$db['bizlms']['db_debug'] = TRUE;
$db['bizlms']['cache_on'] = TRUE;
$db['bizlms']['cachedir'] = '';
$db['bizlms']['char_set'] = 'utf8';
$db['bizlms']['dbcollat'] = 'utf8_general_ci';
$db['bizlms']['swap_pre'] = '';
$db['bizlms']['autoinit'] = TRUE;
$db['bizlms']['stricton'] = TRUE;
Now In My View I have a row in which I fetch data from default database.
And then in second row I want data from another database so, I load that database:
$this->db = $this->load->database('bizlms', TRUE);
But I for my first row where I fetch data from the default database I get an error:
Table bizlms.tablname doesn't exist
How to use both database on same view?
我想从两个不同的数据库访问数据。 p>
我想要 将两个数据库中的记录打印到同一视图中。 p>
现在我的第一个查询来自另一个数据库，然后第二个查询来自默认数据库。 所以我得到一个错误，SecondDatabase.tablenmae不存在，实际上该表在默认数据库中 p>
所以我这样定义它们： p>
$ active_group ='default';
$ active_record = TRUE;
$ db ['default'] ['hostname'] ='localhost';
$ db ['default'] ['username'] ='root';
$ db ['default'] ['password'] ='';
$ db ['default'] ['database'] ='biz_prov';
$ db ['default' ] ['dbdriver'] ='mysql';
$ db ['default'] ['dbprefix'] ='';
$ db ['default'] ['pconnect'] = TRUE;
$ db ['default'] ['db_debug'] = TRUE;
$ db ['default'] ['cache_on'] = FALSE;
$ db ['default'] ['cachedir'] ='';
$ db ['default'] ['char_set'] ='utf8';
$ db ['default'] ['dbcollat'] ='utf8_general_ci';
$ db ['default'] ['swap_pre'] ='';
$ db ['default'] ['autoinit'] = TRUE;
$ db ['default'] ['stricton'] = FALSE;
$ db ['bizlms'] [ 'hostname'] ='localhost';
$ db ['bizlms'] ['username'] ='root';
$ db ['bizlms'] ['password'] ='';
$ db ['bizlms'] ['database'] ='bizlms';
$ db ['bizlms'] ['dbdriver'] ='mysql';
$ db ['bizlms'] ['dbprefix'] ='';
$ db ['bizlms'] ['pconnect'] = FALSE;
$ db ['bizlms'] ['db_debug'] = TRUE;
$ db ['bizlms'] ['cache_on '] = TRUE;
$ db ['bizlms'] ['cachedir'] ='';
$ db ['bizlms'] ['char_set'] ='utf8';
$ db ['bizlms' ] ['dbcollat'] ='utf8_general_ci';
$ db ['bizlms'] ['swap_pre'] ='';
$ db ['bizlms'] ['autoinit'] = TRUE;
$ db ['bizlms'] ['stricton'] = TRUE;
code> pre>
现在在我的视图中，我有一行从默认数据库中获取数据。 p >
然后在第二行我想要来自另一个数据库的数据，所以我加载了该数据库： p>
$ this-＆gt; db = $ this- ＆gt; load-＆gt;数据库（'bizlms'，TRUE）;
code> pre>
但我在第一行从默认数据库中获取数据我收到错误 ： p>
表bizlms.tablname不存在 p>
blockquote>
如何在同一视图上使用这两个数据库 ？ p>
div>
Try like this, keep db name in one variable and use that variable to fetch the data:
<?php
$dsn1 = 'mysql://root@localhost/biz_prov';
$db1 = $this->load->database($dsn1, true);
$user_table = $this->session->userdata('user_table');
$db1->select($user_table.'.id,display_name,ext,email,auth_user,base_ini_filename,base_ini_id,custom_ini_filename,uc_user,uc_password');
$db1->where($user_table.'.site_key',$site_item);
$db1->join('base_ini','base_ini.id ='.$user_table.'.base_ini_id');
$db1->from($user_table);
$query = $db1->get();
$result = $query->result_array();
?>
Yes, you can use 2 or more database to get info and then display it on a view
application/config/database.php
$active_group = 'default';
$db['default']['hostname'] = "host";
$db['default']['username'] = "username";
$db['default']['password'] = "password";
$db['default']['database'] = "database1";
$db['default']['dbdriver'] = "mysqli";
$db['default']['dbprefix'] = "";
$db['default']['pconnect'] = TRUE;
$db['default']['db_debug'] = TRUE;
$db['default']['cache_on'] = FALSE;
$db['default']['cachedir'] = "";
$db['default']['char_set'] = "utf8";
$db['default']['dbcollat'] = "utf8_general_ci";
$db['stats']['hostname'] = "host2";
$db['stats']['username'] = "username";
$db['stats']['password'] = "password";
$db['stats']['database'] = "database2";
$db['stats']['dbdriver'] = "mysqli";
$db['stats']['dbprefix'] = "";
$db['stats']['pconnect'] = TRUE;
$db['stats']['db_debug'] = TRUE;
$db['stats']['cache_on'] = FALSE;
$db['stats']['cachedir'] = "";
$db['stats']['char_set'] = "utf8";
$db['stats']['dbcollat'] = "utf8_general_ci";
controller.php
function do_somthing(){
$this->load->model(array('model_db1', 'model_db2'));
$info_db1 = $this->model_db1->get_info1();
$info_db2 = $this->model_db2->get_info2();
$data = array(
'info1' => $info_db1,
'ifno2' => $info_db2
);
$this->load->view('view', $data);
}
model_db1.php
public function __construct(){
parent::__construct();
$database1 = $this->load->database('default', TRUE);
}
function get_ifno1(){
return $database1->db->get('table')->result();
}
model_db2.php
public function __construct(){
parent::__construct();
$database2 = $this->load->database('stats', TRUE);
}
function get_ifno2(){
return $database2->db->get('table')->result();
}
view.php
<div>
<?php var_dump($info1)?>
</div>
<hr>
<div>
<?php var_dump($info2)?>
</div>