jqGrid获取不到填充报表之外的JSON数据
jqGrid获取不到填充表格之外的JSON数据
json = {"total":6,"page":1,"records":55,"userName":"管理员","rows":
[{
"ID":"12345","TC_CODE":"0077","TC_NAME":"fg","BEGINDATE":"2015-08-11","ENDDATE":"2015-08-13",
"ID":"12345","TC_CODE":"0077","TC_NAME":"fg","BEGINDATE":"2015-08-11","ENDDATE":"2015-08-13"
"ID":"12345","TC_CODE":"0077","TC_NAME":"fg","BEGINDATE":"2015-08-11","ENDDATE":"2015-08-13"
}]}
在jqgrid中我想获取 username 的值该怎么获取
------解决思路----------------------
jqGrid自定义数据
更多:jqGrid中文API
------解决思路----------------------
正解呀!
官方的意思是要用指定名称userdata,你把自定义的数据塞到userdata这个变量就行了。userdata符合json格式,不就可以嵌套任何结构的数据了嘛~
json = {"total":6,"page":1,"records":55,"userName":"管理员","rows":
[{
"ID":"12345","TC_CODE":"0077","TC_NAME":"fg","BEGINDATE":"2015-08-11","ENDDATE":"2015-08-13",
"ID":"12345","TC_CODE":"0077","TC_NAME":"fg","BEGINDATE":"2015-08-11","ENDDATE":"2015-08-13"
"ID":"12345","TC_CODE":"0077","TC_NAME":"fg","BEGINDATE":"2015-08-11","ENDDATE":"2015-08-13"
}]}
在jqgrid中我想获取 username 的值该怎么获取
------解决思路----------------------
jqGrid自定义数据
更多:jqGrid中文API
------解决思路----------------------
正解呀!
官方的意思是要用指定名称userdata,你把自定义的数据塞到userdata这个变量就行了。userdata符合json格式,不就可以嵌套任何结构的数据了嘛~
{
total: "xxx",
page: "yyy",
records: "zzz",
userdata: {totalinvoice:240.00, tax:40.00},
rows : [
{id:"1", cell:["cell11", "cell12", "cell13"]},
{id:"2", cell:["cell21", "cell22", "cell23"]},
//...
]
}