php表单无法获取值,该如何解决

php表单无法获取值
	<p><span class="top-head">密 码 :</span>
    <label for="password"></label>
  <input name="password" type="text" id="password" value="请输入密码">
  </p>
  <p>&nbsp;</p>
  <p>&nbsp;</p>
<p><span class="top-head">密 码 :</span>
                      <label for="password2"></label>
                      <input name="password2" type="text" id="password2" value="请再次密码">
                    </p>
<p>&nbsp;</p>
<p>&nbsp;</p>
  <p><span class="top-head">邮 箱 :</span>
                    <label for="password3"></label>
                    <input name="password3" type="text" id="password3" value="请输入您的邮箱">
                    </p>
<p>&nbsp;</p>
<p>&nbsp;</p>
<p><span class="top-head">授权码:</span>
                      <label for="password4"></label>
                      <input name="password4" type="text" id="password4" value="请输入授权码">
                    </p>
<p>&nbsp;</p>
<p>&nbsp;</p>
  <hr>
<p>
  <script type="text/javascript" src="js/fliplightbox.min.js"></script>
      <script type="text/javascript">$('body').flipLightBox()</script>
</p>
<p>&nbsp;</p>
<form name="form2" method="post" action="login.php">
<input type="submit" name="ann03" id="ann03" value="提 交">
                    
  </form>
                   <?php 
     if(isset($_POST['ann03']))
   { 
      
   $username = $_POST['password'];
   echo "您输入的用户名是:".$username;
  
   }
?>


无法打印出密码
------解决思路----------------------
form表单应该包住所有input输入<form name="form2" method="post" action="login.php">提前到input开始之前的地方即可
------解决思路----------------------
用post接受的,可是没看到password的表单,代码没贴全??
------解决思路----------------------
改为这样就可以了。

<form name="form2" method="post" action="login.php">
<p><span class="top-head">密 码 :</span>
    <label for="password"></label>
  <input name="password" type="text" id="password" value="请输入密码">
  </p>
  <p>&nbsp;</p>
  <p>&nbsp;</p>
<p><span class="top-head">密 码 :</span>
                      <label for="password2"></label>
                      <input name="password2" type="text" id="password2" value="请再次密码">
                    </p>
<p>&nbsp;</p>
<p>&nbsp;</p>
  <p><span class="top-head">邮 箱 :</span>
                    <label for="password3"></label>
                    <input name="password3" type="text" id="password3" value="请输入您的邮箱">
                    </p>
<p>&nbsp;</p>
<p>&nbsp;</p>
<p><span class="top-head">授权码:</span>
                      <label for="password4"></label>
                      <input name="password4" type="text" id="password4" value="请输入授权码">
                    </p>
<p>&nbsp;</p>
<p>&nbsp;</p>
  <hr>
<p>
  <script type="text/javascript" src="js/fliplightbox.min.js"></script>
      <script type="text/javascript">$('body').flipLightBox()</script>
</p>
<p>&nbsp;</p>

<input type="submit" name="ann03" id="ann03" value="提 交">
                    
  </form>
                   <?php 
     if(isset($_POST['ann03']))
   { 
      
   $username = $_POST['password'];
   echo "您输入的用户名是:".$username;
  
   }
?>

------解决思路----------------------
form都没有 算啥表单啊