在PHP中解析Json字符串从数组获取值[重复]

问题描述：

This question already has an answer here:

How can I parse a JSON file with PHP? 16 answers

{
    "DeviceTicketInfo ": {
        "UserId ": 27,
        "Ticket ": 18005956,
        "DevInfo ": "sunsoft-123456 "
    },
    "AvailableStations ": [{
        "Id ": 2,
        "No ": 2,
        "Name ": "01-SUNSOFT "
    }]
}

I want to echo only the UserId from the above json string in php.

Please help

</div>

此问题已经存在这里有一个答案： p>

如何用PHP解析JSON文件？ 16 answers \ r span> li> ul> div>

  {
“DeviceTicketInfo”：{\  n“UserId”：27，
“Ticket”：18005956，
“DevInfo”：“sunsoft-123456”
}，
“AvailableStations”：[{
“Id”：2，
“否 “：2，
”名称“：”01-SUNSOFT“
}] 
} 
  code>  pre> 
 
 我想只回显 UserId 来自 php  code>中的 json  code>字符串。 p> 
 
 
请帮助 p> 
  div>

答

For any json formatted strings, or array, you can simply use the json_encode/json_decode PHP built-in functions.

To decode that json just do something the json_decode() function:

$jsonString = '{
    "DeviceTicketInfo ": {
        "UserId ": 27,
        "Ticket ": 18005956,
        "DevInfo ": "sunsoft-123456 "
    },
    "AvailableStations ": [{
        "Id ": 2,
        "No ": 2,
        "Name ": "01-SUNSOFT "
    }]
}';

$array = json_decode($jsonString, true);

This will return a 2-d array with key=>value pairs.

答

You'll need to convert the json string into a PHP object before accessing its properties, json_decode() is your friend here, i.e.:

$_json = '{ "DeviceTicketInfo":{ "UserId":27, "Ticket ":18005956, "DevInfo ": "sunsoft-123456 "}, "AvailableStations ":[{ "Id ":2, "No ":2, "Name ": "01-SUNSOFT "}]}';
$_json = json_decode($_json);
print_r($_json->DeviceTicketInfo->UserId);
# 27

You can also use true as 2nd argument in json_decode($_json, true); to converted the returned object into an associative array, then you can access the elements using:

$_json['DeviceTicketInfo']['UserId'];

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在PHP中解析Json字符串从数组获取值[重复]

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