使用正则表达式在URL中查找IDENTIFIER并以字符串形式返回

问题描述：

I've got a PHP script that does batch wgets from a database, but need to create a mechanism to generate folders so I can loop it all to save each file in its own folder...

Can one use regex to find the IDENTIFIER (which can be anything/any length, sometimes with underscores, sometimes with hyphens other times not) in following URL or is there some other way? I have no idea about regex...

http://cdn.blah.com/mp4/IDENTIFIER/somefile.mp4

For example, can one find IDENTIFIER and return it as a string? That way I can pass it to write "wget -O /somedir/" . $IDENTIFIER . "/"; and that would help greatly!

Any help very appreciated. Thanks!

我有一个PHP脚本从数据库执行批处理wgets，但是需要创建一个生成文件夹的机制所以我可以将它全部循环以将每个文件保存在自己的文件夹中... p>

可以使用正则表达式来查找IDENTIFIER（可以是任何/任何长度，有时带下划线，有时在其他时间没有连字符）在以下网址中还是有其他方式吗？我不知道正则表达式... p>

http ：//cdn.blah.com/mp4/IDENTIFIER/somefile.mp4 p>

例如，可以找到IDENTIFIER并将其作为字符串返回吗？这样我就可以传递它来写“wget -O / somedir /”。 $ IDENTIFIER。 “/”; 这将有很大帮助！ p>

任何帮助非常感谢。谢谢！ p> div>

答

You can get the identifier using a combination of dirname() and basename():

$url = 'http://cdn.blah.com/mp4/IDENTIFIER/somefile.mp4';
$identifier = basename(dirname($url));

答

I dunno anything about PHP but I notice that

/.*\/([^/]+)\/[^/]+/.exec(s)

pops IDENTIFIER right out for you.

edit: a very brief Google suggests the PHP equivalent would be

<?php
$subject = "http://cdn.blah.com/mp4/IDENTIFIER/somefile.mp4";
$pattern = "/.*\/([^/]+)\/[^/]+/";
preg_match($pattern, $subject, $matches, PREG_OFFSET_CAPTURE);
print_r($matches);
?>

使用正则表达式在URL中查找IDENTIFIER并以字符串形式返回

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