请大家帮小弟我看看,是哪出了有关问题。为什么输入”1,小风“。输出的“1,乱码”
请大家帮我看看,是哪出了问题。为什么输入”1,小风“。输出的“1,乱码”
#include<stdio.h>
#include<stdlib.h>
struct stu
{
int num;
char name[7];
};
int main()
{
struct stu boy1;
struct stu *p;
FILE *fp;
p=&boy1;
if((fp=fopen("D:\\xin","w+"))==NULL)
{
printf("Cannot open the file input num to exit\n");
getchar();
exit(1);
}
printf("input your information\n");
scanf("%d,%s",&p->num,p->name);
printf("%d,%s",p->num,p->name);
return 0;
}
------解决思路----------------------
你输入的是中文的逗号吧,scanf函数中要求的可是英文的
------解决思路----------------------
嗯,他说的没啥错……
------解决思路----------------------
仅供参考:
#include<stdio.h>
#include<stdlib.h>
struct stu
{
int num;
char name[7];
};
int main()
{
struct stu boy1;
struct stu *p;
FILE *fp;
p=&boy1;
if((fp=fopen("D:\\xin","w+"))==NULL)
{
printf("Cannot open the file input num to exit\n");
getchar();
exit(1);
}
printf("input your information\n");
scanf("%d,%s",&p->num,p->name);
printf("%d,%s",p->num,p->name);
return 0;
}
------解决思路----------------------
你输入的是中文的逗号吧,scanf函数中要求的可是英文的
------解决思路----------------------
嗯,他说的没啥错……
------解决思路----------------------
仅供参考:
#include <stdio.h>
char s[]="123 ab 4";
char *p;
int v,n,k;
void main() {
p=s;
while (1) {
k=sscanf(p,"%d%n",&v,&n);
printf("k,v,n=%d,%d,%d\n",k,v,n);
if (1==k) {
p+=n;
} else if (0==k) {
printf("skip char[%c]\n",p[0]);
p++;
} else {//EOF==k
break;
}
}
printf("End.\n");
}
//k,v,n=1,123,3
//k,v,n=0,123,3
//skip char[ ]
//k,v,n=0,123,3
//skip char[a]
//k,v,n=0,123,3
//skip char[b]
//k,v,n=1,4,2
//k,v,n=-1,4,2
//End.