求大神解答着实找不出毛病在哪里

求大神解答实在找不出毛病在哪里
#define __STDC_WANT_LIB_EXT1__ 1//说明：出入数字，输出对应英文
#include<stdio.h>
#include<string.h>
#include<stdbool.h>
#include<ctype.h>
int main(void)
{
char again='Y';
do
{
int num;//数字
char result[100] = "";//结果
size_t result_len = sizeof(result);
char connect1[10] = " hundred";//连接1
char connect2[10] = " and ";//连接2
char a[10][7] = {
" ","One","Two","Three","Four","Five","Six ","Seven ","Eight ","Nine "//百位
};
char b[10][8] = {
" "," ","twenty ","thirty ","forty ","fifty ","sixty ","seventy ","eighty ","ninty "//十位
};
char c[10][7] = {
" ","one","two","three","four","five","six ","seven ","eight ","nine "//个位
};

while (true)//检查输入是否在0-1000
{
printf("\nEnter a number less than 1000.\n");
scanf("%d", &num);
if ((num < 0) || (num>999))
printf("You are kidding.Enter again.");
else
break;
}
//形成最终结果
int g = num / 100;
num = num - g * 100;

if (strcat_s(result, result_len, a[g]))
{
printf("Error");
return 1;
}
if (a[g][0] != ' ')
strcat_s(result, result_len, connect1);
if ((num > 0) && (g != 0))
strcat_s(result, result_len, connect2);
g = num / 10;
if (strcat_s(result, result_len, b[g]))
{
printf("Error");
return 2;
}
num = num - g * 10;
g = num;
if (strcat_s(result, result_len, c[g]))
{
printf("Error");
return 3;
}
printf("%s", result);//输出结果
printf("\nDo you want to try again? Y or N\n");//判断是否重复操作
scanf("%c", &again);
} while (toupper(again) =='Y');
getch();
return 0;
}

------解决思路----------------------

scanf(" %c", &again);//"和%之间添加一个空格？

------解决思路----------------------
最后的scanf前加一个 getchar(); 接收掉前面输入时留下的换行符
同时char b[10][8] 这里改成char[10][9]，不然"seventy "就溢出了

修改后代码：



int main(void)

{

	char again='Y';

	do

	{

		int num;//数字

		char result[100] = "";//结果

		size_t result_len = sizeof(result);

		char connect1[10] = " hundred";//连接1

		char connect2[10] = " and ";//连接2

		char a[10][7] = {

			" ","One","Two","Three","Four","Five","Six ","Seven ","Eight ","Nine "//百位

		};

		char b[10][9] = {

			" "," ","twenty ","thirty ","forty ","fifty ","sixty ","seventy ","eighty ","ninty "//十位

		};

		char c[10][7] = {

			" ","one","two","three","four","five","six ","seven ","eight ","nine "//个位

		};


		while (true)//检查输入是否在0-1000

		{

			printf("\nEnter a number less than 1000.\n");

			scanf("%d", &num);

			if ((num < 0) 
------解决思路----------------------
 (num>999))

				printf("You are kidding.Enter again.");

			else

				break;

		}

		//形成最终结果

		int g = num / 100;

		num = num - g * 100;


		if (strcat_s(result, result_len, a[g]))

		{

			printf("Error");

			return 1;

		}

		if (a[g][0] != ' ')

			strcat_s(result, result_len, connect1);

		if ((num > 0) && (g != 0))

			strcat_s(result, result_len, connect2);

		g = num / 10;

		if (strcat_s(result, result_len, b[g]))

		{

			printf("Error");

			return 2;

		}

		num = num - g * 10;

		g = num;

		if (strcat_s(result, result_len, c[g]))

		{

			printf("Error");

			return 3;

		}

		printf("%s", result);//输出结果

		printf("\nDo you want to try again? Y or N\n");//判断是否重复操作

		getchar();

		scanf("%c", &again);

	} while (toupper(again) =='Y');

	getch();

	return 0;

}

------解决思路----------------------

引用:

是不是scanf读取到enter之后会停止，而enter留在缓冲区队列里？

scanf 读到空格会暂停，后面的就回留到缓冲区。
scanf 读到enter会暂停，enter留在缓冲区，如果后面还有定义的变量，会赋值给后面的变量。
ag.
scanf("%d",&a);
scanf("%c",&c);
输入a回车，c就会是回车字符

求大神解答着实找不出毛病在哪里

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