hdu 1251 统计难点 (前缀树)
hdu 1251 统计难题 (前缀树)
题意是:
题意是:
Ignatius最近遇到一个难题,老师交给他很多单词(只有小写字母组成,不会有重复的单词出现),现在老师要他统计出以某个字符串为前缀的单词数量(单词本身也是自己的前缀).
思路很简单,前缀数组入门题,对于每个结点,用val数组记录当前字符串为前缀的字符串数量,之后就是插入,查询操作了
代码如下:
#include<cstdio>
#include<cstring>
#include<cmath>
#include<cstdlib>
#include<iostream>
#include<algorithm>
#include<vector>
#include<map>
#include<queue>
#include<stack>
#include<string>
#include<map>
#include<set>
using namespace std;
#define LL long long
const int maxnode = 1000000 ;
const int sigma_size = 26;
struct Trie {
int ch[maxnode][sigma_size];
int val[maxnode];
int sz;
Trie() { sz = 1; memset(ch[0], 0, sizeof(ch[0]));};
int idx(char c) {return c - 'a';}
void insert(char *s) {
int u = 0, n = strlen(s);
for(int i = 0; i < n; i++) {
int c = idx(s[i]);
if(!ch[u][c]) {
memset(ch[sz], 0, sizeof(ch[sz]));
val[sz] = 1;
ch[u][c] = sz++;
}
else val[ch[u][c]]++;
u = ch[u][c];
}
}
int find(char *s) {
int u = 0, n = strlen(s);
for(int i = 0; i < n; i++) {
int c = idx(s[i]);
if(!ch[u][c]) return 0;
else u = ch[u][c];
}
return val[u];
}
};
Trie trie;
int main() {
char dic[11], qry[11];
//freopen("input.txt", "r", stdin);
while(gets(dic) && strcmp(dic, "") != 0) {
// printf("%s\n", dic);
trie.insert(dic);
}
while(gets(qry)) printf("%d\n", trie.find(qry));
return 0;
}