如何在Golang中复制http.Get（url）请求的响应

问题描述：

I'm trying to use resp, err := http.Get(url) command to write the response to file as well as use the same response to extract links.

After I write the content to a file using resp.Write(f), I cannot use resp.Body for another purpose (for the response from the above url) without making another http.Get request.

I tried resp2 := bytes.NewBuffer(resp). It gives eror as type does not match. I've tried copy as well.

我正在尝试使用resp，err：= http.Get（url） code> 命令将响应写入文件以及使用相同的响应来提取链接。 p>

使用 resp.Write（f） code>将内容写入文件后，不能将 resp.Body code>用于其他目的（用于来自上述url的响应）而没有发出另一个 http.Get code>请求。 p>

我尝试了 resp2：= bytes.NewBuffer（resp）。由于类型不匹配，因此会给出错误。我也尝试过复制。 p> div>

答

Assuming the response fits in memory, just create a buffer and use resp.Write, like (untested, basically correct):

var b bytes.Buffer
if err := resp.Write(b); err != nil {
   // handle error
} else {
    // Do something with buffer
}

for code that works with any reader, use: ioutil.ReadAll, which returns a new []byte containing the data that you can then wrap in a bytes.Buffer

答

httputil has a response dump. https://golang.org/pkg/net/http/httputil/#DumpRequest It will replace the body with an in-memory copy so you can reuse it.

如何在Golang中复制http.Get（url）请求的响应

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