循环使用中多次出现的数组中删除元素

问题描述：

我要在具有多个事件与函数的数组中删除元素。

I want to remove an element in an array with multiple occurrences with a function.

var array=["hello","hello","world",1,"world"];

function removeItem(item){
    for(i in array){
        if(array[i]==item) array.splice(i,1);
    }
}

removeItem("world");
//Return hello,hello,1

removeItem("hello");
//Return hello,world,1,world

这个循环，当它在序列重复两次不删除元素，只删除其中的一个。

This loop doesn't remove the element when it repeats twice in sequence, only removes one of them.

为什么？

答

您有一个内置的函数叫做filter$c$c>该过滤器基于一个predicate（的条件）的数组。

You have a built in function called filter that filters an array based on a predicate (a condition).

这不会改变原来的数组，但返回一个新过滤的。

It doesn't alter the original array but returns a new filtered one.

var array=["hello","hello","world",1,"world"];
var filtered = array.filter(function(element){
    return element !== "hello";
}); // filtered contains no occurrences of hello

您可以将其解压缩到一个功能：

You can extract it to a function:

function without(array, what){
    return array.filter(function(el){ 
        return element !== what;
    });
}

不过，原来的过滤器似乎EX pressive足够了。

However, the original filter seems expressive enough.

Here是它的文档链接

您原有的功能有几个问题：

Your original function has a few issues:

它重复使用为中... 循环具有迭代顺序上没有保证的阵列。此外，不要用它来遍历数组 - preFER正常的。 .. 环或 .forEach

您正在迭代与差一错误让你跳跃上的下一个项目，因为你们都删除元素和进步数组的数组。

It iterates the array using a for... in loop which has no guarantee on the iteration order. Also, don't use it to iterate through arrays - prefer a normal for... loop or a .forEach
You're iterating an array with an off-by-one error so you're skipping on the next item since you're both removing the element and progressing the array.

循环使用中多次出现的数组中删除元素

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