求解正则表达式,该怎么处理
求解正则表达式
源字符串为这个
想把46630489 233 ，46681600 8 匹配出来，该怎么写啊。
------解决方案--------------------
本帖最后由 AfterSeptember 于 2013-12-05 15:41:26 编辑
源字符串为这个
<tr class="">
<td class="title">
<a href="http://www.douban.com/group/topic/46630489/" title="po照会遇见熟人吗？" class="">po照会遇见熟人吗？</a>
</td>
<td nowrap="nowrap"><a href="http://www.douban.com/group/people/toffybobo/" class="">ToTo</a></td>
<td nowrap="nowrap" class="">233</td>
<td nowrap="nowrap" class="time">12-05 11:11</td>
</tr>
<tr class="">
<td class="title">
<a href="http://www.douban.com/group/topic/46681600/" title="今天出门你们有没有戴口罩" class="">今天出门你们有没有戴口罩</a>
</td>
<td nowrap="nowrap"><a href="http://www.douban.com/group/people/1354411/" class="">丛生</a></td>
<td nowrap="nowrap" class="">8</td>
<td nowrap="nowrap" class="time">12-05 11:06</td>
</tr>
想把46630489 233 ，46681600 8 匹配出来，该怎么写啊。
------解决方案--------------------
>>> s = '''<tr class="">
<td class="title">
<a href="http://www.douban.com/group/topic/46630489/" title="po照会遇见熟人吗？" class="">po照会遇见熟人吗？</a>
</td>
<td nowrap="nowrap"><a href="http://www.douban.com/group/people/toffybobo/" class="">ToTo</a></td>
<td nowrap="nowrap" class="">233</td>
<td nowrap="nowrap" class="time">12-05 11:11</td>
</tr>
<tr class="">
<td class="title">
<a href="http://www.douban.com/group/topic/46681600/" title="今天出门你们有没有戴口罩" class="">今天出门你们有没有戴口罩</a>
</td>
<td nowrap="nowrap"><a href="http://www.douban.com/group/people/1354411/" class="">丛生</a></td>
<td nowrap="nowrap" class="">8</td>
<td nowrap="nowrap" class="time">12-05 11:06</td>
</tr>'''
>>> import re
>>> res = r'topic/(\d+?)/.*?class="">(\d+?)</td>'
>>> m = re.findall(res,s,re.S
------解决方案--------------------
re.M)
>>> m
[('46630489', '233'), ('46681600', '8')]