窗口弹出有关问题,进来瞅瞅
窗口弹出问题,进来瞅瞅
[code=HTML][/code]
<!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN">
<html>
<head>
<title>Menu.html</title>
<meta http-equiv="keywords" content="keyword1,keyword2,keyword3">
<meta http-equiv="description" content="this is my page">
<meta http-equiv="content-type" content="text/html; charset=UTF-8">
<link rel="stylesheet" href="Menu.css" type="text/css"></link>
<script language="javascript" type="text/javascript">
function Show(val){
if(val=="menu"){
document.getElementById("menu").style.display="block";
}
}
function Close(val){
if(val=="menu"){
document.getElementById("menu").style.display="none";
}
}
</script>
</head>
<body>
<div class="all">
<ul>
<li onmouseover="Show('menu')" onmousemove="Close('menu')"><a href="#" ></a>菜单</li>
<li><table class="menu" id="menu">
<tr><td><ul><li><a href="#"></a>注册</li>
<li><a href="#"></a>登入</li>
<li><a href="#"></a>监测</li></ul></td></tr>
</table>
</li>
</ul>
</div>
</body>
</html>
[code=CSS][/code]
.all{
width:100px;
background-color: gray;
border: 2px solid blue;
text-align: center;
}
.all ul{
list-style-type: none;
padding: 0;
margin: 0;
}
.menu {
display: none;
}
弹出的窗口为何只是闪出来一下就没了
------解决方案--------------------
<li onmouseover="Show('menu')" onmousemove="Close('menu')">
这个是什么情况?是不是第二个要写成onmouseout
------解决方案--------------------
[code=HTML][/code]
<!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN">
<html>
<head>
<title>Menu.html</title>
<meta http-equiv="keywords" content="keyword1,keyword2,keyword3">
<meta http-equiv="description" content="this is my page">
<meta http-equiv="content-type" content="text/html; charset=UTF-8">
<link rel="stylesheet" href="Menu.css" type="text/css"></link>
<script language="javascript" type="text/javascript">
function Show(val){
if(val=="menu"){
document.getElementById("menu").style.display="block";
}
}
function Close(val){
if(val=="menu"){
document.getElementById("menu").style.display="none";
}
}
</script>
</head>
<body>
<div class="all">
<ul>
<li onmouseover="Show('menu')" onmousemove="Close('menu')"><a href="#" ></a>菜单</li>
<li><table class="menu" id="menu">
<tr><td><ul><li><a href="#"></a>注册</li>
<li><a href="#"></a>登入</li>
<li><a href="#"></a>监测</li></ul></td></tr>
</table>
</li>
</ul>
</div>
</body>
</html>
[code=CSS][/code]
.all{
width:100px;
background-color: gray;
border: 2px solid blue;
text-align: center;
}
.all ul{
list-style-type: none;
padding: 0;
margin: 0;
}
.menu {
display: none;
}
弹出的窗口为何只是闪出来一下就没了
------解决方案--------------------
<li onmouseover="Show('menu')" onmousemove="Close('menu')">
这个是什么情况?是不是第二个要写成onmouseout
------解决方案--------------------
- HTML code
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> <html xmlns="http://www.w3.org/1999/xhtml"> <head> <title>导航菜单</title> <meta http-equiv="Content-Type" content="text/html; charset=UTF-8"/> <style type="text/css"> .menu{width:100%;} .menu ul{float:left;list-style:none;width:100%;} .menu li{float:left;list-style:none;text-align:left;margin-left:10px;width:106px;height:20px;position:relative;} .menu li span{float:left;width:60px;display:none;background:#fff; position:absolute;border:1px solid #bfbfbf;left:-15px;top:20px;/*因为position的定义,实际上该区域原点仍为父级标签的原点,因此设置一个top偏离*/} .menu li span a{float:left;width:100%;color: #4454AB;text-align:center;height:28px;line-height:28px;text-decoration:none;} .menu li span a:hover{color: #ff9900;} </style> <script type="text/javascript"> function MenuEventListen(){ var _menu=document.getElementById("menu"); var _li=_menu.getElementsByTagName("li"); for(i=0;i<_li.length;i++) { _li[i].onmouseover=function(){ this.getElementsByTagName('span')[0].style.display='block'; }; _li[i].onmouseout=function(){ this.getElementsByTagName('span')[0].style.display='none'; }; } } window.onload=function(){ MenuEventListen(); } </script> </head> <body> <div id="menu" class="menu"> <ul> <li> <a href="#">菜单</a> <span><a href="#">注册</a><a href="#">登入</a><a href="#">监测</a></span> </li> </ul> </div> <div>这里是其他内容,这里是其他内容</div> </body> </html>