java 如何替换掉一行数据

java 怎么替换掉一行数据
0000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000 IP：Port117.136.6.213:20517*******************

把最后的ip到******删除
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确定是Ip 到行尾的那一部分吗，如果IP 那一段就是在行尾的话

int iLocation = str.indexOf("I");

System.out.println(str.substring(0, iLocation));

就可以了
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因为我没在电脑旁，所以我没发逞上代码，我给楼主一个解决方案，你可以试下，先用字符串的LastIndexOf（0）就是截取到最后一数字0，然后会返回一个int整数，这个整数代表的是最后一个0的位置，接下来楼主可以写字符串的另一个方法substring（0,写上你刚才返回的那个int整数，这样楼主就可以得到心中的字符串，希望能帮到楼主！
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结尾是****?那用正则方便了...