请高手帮小弟我分析一上这个多线程的小练习程序

请高手帮我分析一下这个多线程的小练习程序。
这个是我按照孙鑫C++视频里面的练习做的我得编程环境是vs2010+win7
代码如下：

C/C++ code

#include<iostream>
#include <windows.h>
using namespace std;

DWORD WINAPI GThreadProc1(
    __in  LPVOID lpParameter
    );

DWORD WINAPI GThreadProc2(
    __in  LPVOID lpParameter
    );

int tickets=100;
HANDLE hMutex;
int main()
{
    HANDLE hThread1;
    HANDLE hThread2;

    hThread1=CreateThread(NULL,0,GThreadProc1,NULL,0,NULL);
    hThread2=CreateThread(NULL,0,GThreadProc2,NULL,0,NULL);
    
    Sleep(5000);
    hMutex=CreateMutex(NULL,false,NULL);
    return 0;
}
DWORD WINAPI GThreadProc1(
    __in  LPVOID lpParameter
    )
{
    
    WaitForSingleObject(hMutex,INFINITE);
    while (true)
    {
        Sleep(1);
        if (tickets>0)
        {
            cout<<"No.1 seller sells ticket :"<<tickets--<<endl;
        }
        ReleaseMutex(hMutex);
    }
    return 0;
}

DWORD WINAPI GThreadProc2(
    __in  LPVOID lpParameter
    )
{
    
    WaitForSingleObject(hMutex,INFINITE);
    while (true)
    {
        Sleep(1);
        if (tickets>0)
        {
            cout<<"No.2 seller sells ticket :"<<tickets--<<endl;
            ReleaseMutex(hMutex);
        }
    }
    return 0;
}

为什么会出现如下图所示的运行结果：

如果我把代码中两个线程的sleep(1)去掉又会出现如下两图所示的情况
1

2

我的理想状况是让他们按照顺序卖票。请问出现以上情况的原理原因是什么啊？希望高手多多帮助。

------解决方案--------------------
多线程互斥量

sleep在互斥量的保护范围之内

不知道你是否是把两个sleep同时去除的呢？？
------解决方案--------------------
#include<iostream>
#include <windows.h>
using namespace std;

DWORD WINAPI GThreadProc1(
__in LPVOID lpParameter
);

DWORD WINAPI GThreadProc2(
__in LPVOID lpParameter
);

int tickets=100;
HANDLE hMutex;
int main()
{
HANDLE hThread1;
HANDLE hThread2;

hMutex=CreateMutex(NULL,false,NULL);

hThread1=CreateThread(NULL,0,GThreadProc1,NULL,0,NULL);
hThread2=CreateThread(NULL,0,GThreadProc2,NULL,0,NULL);

Sleep(5000);

system("pause");

return 0;
}
DWORD WINAPI GThreadProc1(
__in LPVOID lpParameter
)
{

while (true)
{
WaitForSingleObject(hMutex,INFINITE);
if (tickets>0)
{
cout<<"No.1 seller sells ticket :"<<tickets--<<endl;
}
else
{
break;
}
ReleaseMutex(hMutex);
}
return 0;
}

DWORD WINAPI GThreadProc2(
__in LPVOID lpParameter
)
{

while (true)
{
WaitForSingleObject(hMutex,INFINITE);
if (tickets>0)
{
cout<<"No.2 seller sells ticket :"<<tickets--<<endl;
ReleaseMutex(hMutex);
}
else
{
break;
}
}
return 0;
}

------解决方案--------------------
你线程2的ReleaseMutex(hMutex)语句写错了吧;
怎么写到if语句里面啊。。要是不满足条件，。。。那不是就执行不了ReleaseMutex(hMutex);
所以会出现那种情况

------解决方案--------------------
上面没贴好

C/C++ code


#include<iostream>
#include <windows.h>
using namespace std;

DWORD WINAPI GThreadProc1(
    LPVOID lpParameter
    );

DWORD WINAPI GThreadProc2(
    LPVOID lpParameter
    );

int tickets=100;
//HANDLE hMutex;
CRITICAL_SECTION g_cs;
int main()
{
    HANDLE hThread1;
    HANDLE hThread2;
    
    InitializeCriticalSection(&g_cs);
    //hMutex=CreateMutex(NULL,false,NULL);
    hThread1=CreateThread(NULL,0,GThreadProc1,NULL,0,NULL);
    hThread2=CreateThread(NULL,0,GThreadProc2,NULL,0,NULL);
    Sleep(5000);
    CloseHandle(hThread1);
    CloseHandle(hThread2);
    DeleteCriticalSection(&g_cs);
    return 0;
}
DWORD WINAPI GThreadProc1(
      LPVOID lpParameter
    )
{
    
    //WaitForSingleObject(hMutex,INFINITE);
    while (true)
    {
        ::EnterCriticalSection(&g_cs);
        Sleep(1);
        if (tickets>0)
        {
            cout<<"No.1 seller sells ticket :"<<tickets--<<endl;
        }
        ::LeaveCriticalSection(&g_cs);
        //ReleaseMutex(hMutex);
    }
    return 0;
}

DWORD WINAPI GThreadProc2(
      LPVOID lpParameter
    )
{
    
    //WaitForSingleObject(hMutex,INFINITE);
    while (true)
    {
        ::EnterCriticalSection(&g_cs);
        Sleep(1);
        if (tickets>0)
        {
            cout<<"No.2 seller sells ticket :"<<tickets--<<endl;
            //ReleaseMutex(hMutex);
        }
        ::LeaveCriticalSection(&g_cs);
    }
    return 0;
}

请高手帮小弟我分析一上这个多线程的小练习程序

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