数据统计有关问题,求指点
数据统计问题,求指点
一名语句,统计出Type为1与2各自的count数,当ID一样时,计为1,请大牛指点,非常感谢
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- SQL code
数据: ID PID UserID Type Time 714 1276 2771 2 2012-04-14 13:15:02.427 714 1340 2771 2 2012-04-14 13:15:02.427 714 1525 2771 2 2012-04-14 13:15:02.427 714 12011 2771 2 2012-06-14 18:15:09.223 714 12194 2771 2 2012-06-21 14:00:00.000 723 12599 2771 1 2012-07-04 14:00:00.000 723 1289 2771 1 2012-04-14 13:15:02.427 723 2138 2771 1 2012-04-14 13:15:02.427 724 1867 2771 1 2012-04-14 13:15:02.427 724 1928 2771 1 2012-04-14 13:15:02.427 724 1290 2771 1 2012-04-14 13:15:02.427 724 1292 2771 1 2012-04-14 13:15:02.427 724 1323 2771 1 2012-04-14 13:15:02.427 724 12233 2771 1 2012-06-22 11:00:00.000 724 12497 2771 1 2012-07-02 14:00:00.000 724 12207 2771 1 2012-06-21 11:00:00.000 743 12775 2771 1 2012-07-11 11:00:00.000 743 1317 2771 1 2012-04-14 13:15:02.427 743 1531 2771 1 2012-04-14 13:15:02.427 743 1858 2771 1 2012-04-14 13:15:02.427 743 1958 2771 1 2012-04-14 13:15:02.427 813 2036 2771 1 2012-04-14 13:15:02.427 813 2135 2771 1 2012-04-14 13:15:02.427
一名语句,统计出Type为1与2各自的count数,当ID一样时,计为1,请大牛指点,非常感谢
------解决方案--------------------
- SQL code
SELECT TYPE,COUNT(DISTINCT ID) AS CNT FROM TB GROUP BY TYPE