关于struct的golang语法问题

问题描述：

here is some codes, but it is so long and unnecessary. Sometimes I need to write somethings to mysql, there is some kind of tables like that.

I have been try to use interface{}, but it is more complex.

Is there any way to make it shorter?

type One struct{
    Id int
    Name String
    Status bool
    Devtype string
    ...
    Created time.Time
}

type Two struct{
    Id int
    Name String
    Status bool
    Devtype string
    ...
    Created time.Time
}

type Three struct{
    Id int
    Name String
    Status bool
    Devtype string
    ...
    Created time.Time
}

func Insert(devtype string){
    if devtype == "one"{
        var value One
        value.Id = 1
        value.Name = "device"
        value.Status = false
        value.Devtype = devtype //only here is different
        value.Created = time.Now()
        fmt.Println(value)
    }else if devtype == "two"{
        var value Two
        value.Id = 1
        value.Name = "device"
        value.Status = false
        value.Devtype = devtype //only here is different
        value.Created = time.Now()
        fmt.Println(value)
    }else if devtype == "three"{
        var value Three
        value.Id = 1
        value.Name = "device"
        value.Status = false
        value.Devtype = devtype //only here is different
        value.Created = time.Now()
        fmt.Println(value)
    }
}

这是一些代码，但是它是如此之长且不必要。有时我需要向mysql写一些东西，\ nthere是类似的表。 p>

我一直在尝试使用interface {}，但它更复杂。 p>

有没有 p>

  type一个结构{
 ID int 
名称字符串
状态布尔值
 Devtype字符串
 ... 
创建时间。 时间
} 
 
type两个结构{
 ID int 
名称字符串
状态布尔值
 Devtype字符串
 ... 
创建的时间。时间
} 
 
type三个结构{
  Id int 
名称字符串
状态布尔值
 Devtype字符串
 ... 
创建的时间。时间
} 
 
func Insert（devtype string）{
 if devtype ==“ one” {
  var值一个
值。Id= 1 
值。名称=“ device” 
值。状态= false 
值。Devtype= devtype //仅此一个
值。Created= time.Now（）  
 fmt.Println（value）
}否则，如果devtype =  =“ two” {
 var value Two 
 value.Id = 1 
 value.Name =“ device” 
 value.Status = false 
 value.Devtype = devtype //这里只有不同的
值。 创建= time.Now（）
 fmt.Println（value）
}否则，如果devtype ==“ three” {
 var value Three 
 value.Id = 1 
 value.Name =“ device” 
  value.Status = false 
 value.Devtype = devtype //只有此处是不同的
 value.Created = time.Now（）
 fmt.Println（value）
} 
} 
  code>  
  div>

答

golang's struct inherit will help this

type Base struct {
    Id int
    Name String
    Status bool
    ...
    Created time.Time
}

type One struct{
    Base
    Devtype string
}

type Two struct{
    Base
    Devtype string
}

type Three struct{
    Base
    Devtype string
}

func Insert(devtype string, base Base){
    switch devtype {
        case "one"
            var value One
            value.Base = base
            value.Devtype = devtype //only here is different
        case "two"
            var value Two
            value.Base = base
            value.Devtype = devtype //only here is different
        case "three"
            var value Three
            value.Base = base
            value.Devtype = devtype //only here is different
    }
}

PS: since there is noly one field different, it is not a good practice to create three type

关于struct的golang语法问题

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