如何更改客户端选择的图片的名称，并将其保存在具有不同名称的服务器中

问题描述：

I have the following code to upload to my server an image than the user sends through an input type=file.

My questions is: How can I change the name of the file?

Example: let's say than the user upload the following file: "mypicture.jpg" and I want to save it with the name of a variable I have stored, like $username where $username = John so even the user selected "mypicture.jpg" the file will be save in my directory (/var/www/html/images/) as John.jpg

<?php
if ($_SERVER["REQUEST_METHOD"] == "POST") {

$uploaddir = '/var/www/html/images/';
$uploadfile = $uploaddir . basename($_FILES['userfile']['name']);

if (move_uploaded_file($_FILES['userfile']['tmp_name'], $uploadfile)) {
echo "File is valid, and was successfully uploaded.
";
} else {
echo "Possible file upload attack!
";
}
   pg_close();
 }

function test_input($data) {
$data = trim($data);
$data = stripslashes($data);
$data = htmlspecialchars($data);
return $data;
}
?>


<form enctype="multipart/form-data" action="<?php echo htmlspecialchars($_SERVER["PHP_SELF"]);?>" method="POST">
<input type="hidden" name="MAX_FILE_SIZE" value="3000000" />
Send this file: <input name="userfile" type="file" />
<input type="submit" value="Send File" />
</form>

Thank you so much

我有以下代码上传到我的服务器的图像，而不是用户通过input type = file发送的图像。 / p>

我的问题是：如何更改文件名？ p>

示例：假设用户上传以下文件：“mypicture。 jpg“我想用我已存储的变量的名称保存它，比如$ username其中$ username = John所以即使用户选择”mypicture.jpg“文件也会保存在我的目录中（/ var / www / html / images /）如John.jpg p>

 ＆lt;？php 
if（$ _SERVER [“REQUEST_METHOD”] ==“POST”）{
 
 $ uploaddir  ='/ var / www / html / images /'; 
 $ uploadfile = $ uploaddir。  basename（$ _ FILES ['userfile'] ['name']）; 
 
if（move_uploaded_file（$ _ FILES ['userfile'] ['tmp_name']，$ uploadfile））{
echo“文件有效，是 已成功上传。
“; 
}其他{
echo”可能的文件上传攻击！
“; 
} 
 pg_close（）; 
} 
 
function test_input（$ data）{
 $ data  = trim（$ data）; 
 $ data = stripslashes（$ data）; 
 $ data = htmlspecialchars（$ data）; 
return $ data; 
} 
？＆gt; 
 
 
＆lt; form  enctype =“multipart / form-data”action =“＆lt;？php echo htmlspecialchars（$ _ SERVER [”PHP_SELF“]）;？＆gt;”  method =“POST”＆gt; 
＆lt; input type =“hidden”name =“MAX_FILE_SIZE”value =“3000000”/＆gt; 
发送此文件：＆lt; input name =“userfile”type =“file”/＆gt;  
＆lt; input type =“submit”value =“发送文件”/＆gt; 
＆lt; / form＆gt; 
  code>  pre> 
 
 非常感谢 p> \  n  div>

答

$temp = explode(".", $_FILES["file"]["name"]);
$newfilename = $username . '.' . end($temp);
move_uploaded_file($_FILES["file"]["tmp_name"], "/var/www/html/images/" . $newfilename);

如何更改客户端选择的图片的名称，并将其保存在具有不同名称的服务器中

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