是否可以在PHP中的函数内部创建变量全局？

问题描述：

I'm trying to make a function that returns the id number of a certain user, but I can't access a variable that I declared in the function when I'm calling the function.

function loadlink($users){

    global $database, $rowz, $results;
    $results = $database->query("SELECT * FROM users WHERE username = '{$users}'");
    $rowz = $results->fetch_all(MYSQLI_ASSOC);
    var_dump( $rowz); //returns basic array info
}

var_dump( $rowz); //returns "NULL"
loadlink('RandomUser');

var_dump( $rowz); returns the array info if I call loadlink() first, but the thing is that I want to use the $rowz variable when calling loadlink() to access a property of the returned associative array, but it doesn't return anything.

答

You should really return from your function what you need it to return and not use global variables for that.

But yes, it is possible using the $GLOBALS array although you would need to call your function first before you can access the variables you set in it:

function loadlink($users){
    global $database;

    $GLOBALS['results'] = $database->query("SELECT * FROM users WHERE username = '{$users}'");
    $GLOBALS['rowz'] = $results->fetch_all(MYSQLI_ASSOC);
}

// run function first to initialize the necessary variables
loadlink('RandomUser');
var_dump($rowz); //returns basic array info

是否可以在PHP中的函数内部创建变量全局？

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