PyQt Qthread 输出到textBrowser,该如何处理

PyQt Qthread 输出到textBrowser
我的main()程序已经写好,输出大部分是print 输出. 
我现在想使用PyQt 的Qthread, 当点击开始按钮时,main()执行过程中的信息实时输出到textBrowser ,

请问如何connect? 

在网上找到一个例子,但我还是转不过弯来实现我想要的功能. 麻烦使用过的指点下?谢谢.

import sys

from PyQt4 import QtGui, QtCore

import time

import random

 

 

class MyThread(QtCore.QThread):

    trigger = QtCore.pyqtSignal(int)

 

    def __init__(self, parent=None):

        super(MyThread, self).__init__(parent)

 

    def setup(self, thread_no):

        self.thread_no = thread_no

 

    def run(self):

        time.sleep(random.random()*5)  # random sleep to imitate working

        self.trigger.emit(self.thread_no)

 

 

class Main(QtGui.QMainWindow):

    def __init__(self, parent=None):

        super(Main, self).__init__(parent)

        self.text_area = QtGui.QTextBrowser()

        self.thread_button = QtGui.QPushButton('Start threads')

        self.thread_button.clicked.connect(self.start_threads)

 

        central_widget = QtGui.QWidget()

        central_layout = QtGui.QHBoxLayout()

        central_layout.addWidget(self.text_area)

        central_layout.addWidget(self.thread_button)

        central_widget.setLayout(central_layout)

        self.setCentralWidget(central_widget)

 

    def start_threads(self):

        self.threads = []              # this will keep a reference to threads

        for i in range(10):

            thread = MyThread(self)    # create a thread

            thread.trigger.connect(self.update_text)  # connect to it's signal

            thread.setup(i)            # just setting up a parameter

            thread.start()             # start the thread

            self.threads.append(thread) # keep a reference

 

    def update_text(self, thread_no):

        self.text_area.append('thread # %d finished' % thread_no)

 

if __name__ == '__main__':

    app = QtGui.QApplication(sys.argv)

 

    mainwindow = Main()